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3 years ago

PLZZ HELP ASAP!!!!!

Mathematics

2 answers:

seraphim [82]3 years ago

5 0

The answer for this question is, the last option!

*7(8 + 3)*

WORK!!!

56 + 21= 77

7(49 + 14)= 441

8(7 + 21)= 224

8(48 + 13)= 488

7(8 + 3) = 77< --------------- Equivalent!

Lelu [443]3 years ago

4 0

Answer:

The answer is 7(8 + 3)

Step-by-step explanation:

7 x 8 = 56

7 x 3 = 21

pls mark brainlyest:)

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Explain why it is important to line up decimal points when you are adding and subtracting decimals. Use the problem 6.32 – 0.5 i

Mazyrski [523]

Answer:

Kindly check explanation

Step-by-step explanation:

When performing addition and subtraction of decimals, it is important to arrange the numbers being added or subtracted such that the decimal points are in line. This is particularly important so that the place value of the numbers are in accord.

To simplify, when then decimals are in line, then the tenth value of the first number will be added to the tenth value of the second. Without this arrangement, one might be adding the hundredth placed value to the tenth or unit value which is mathematically incorrect and will yield a wrong result.

For instance :

6.32 - 0.5

Here, when the decimal point of each number is in line, the tenth placed value of the first number (3) matches the tenth placed number of the second number (5) and all others also fall in place automatically.

____6.32

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4 0

3 years ago

student randomly receive 1 of 4 versions(A, B, C, D) of a math test. What is the probability that at least 3 of the 5 student te

alexdok [17]

Answer:

1.2%

Step-by-step explanation:

We are given that the students receive different versions of the math namely A, B, C and D.

So, the probability that a student receives version A = $\frac{1}{4}$ .

Thus, the probability that the student does not receive version A = $1-\frac{1}{4}$ = $\frac{3}{4}$ .

So, the possibilities that at-least 3 out of 5 students receive version A are,

1) 3 receives version A and 2 does not receive version A

2) 4 receives version A and 1 does not receive version A

3) All 5 students receive version A

Then the probability that at-least 3 out of 5 students receive version A is given by,

$\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}$

= $(\frac{1}{4})^3\times (\frac{3}{4})^2+(\frac{1}{4})^4\times (\frac{3}{4})+(\frac{1}{4})^5$

= $(\frac{1}{4})^3\times (\frac{3}{4})[\frac{3}{4}+\frac{1}{4}+(\frac{1}{4})^2]$

= $(\frac{3}{4^4})[1+\frac{1}{16}]$

= $(\frac{3}{256})[\frac{17}{16}]$

= 0.01171875 × 1.0625

= 0.01245

Thus, the probability that at least 3 out of 5 students receive version A is 0.0124

So, in percent the probability is 0.0124 × 100 = 1.24%

To the nearest tenth, the required probability is 1.2%.

4 0

3 years ago

3 years from now, Ron's age will be 2 times that of Miley. Three years ago, Ron's age was 3 times that of Miley.

andrezito [222]

Answer:

M=9

EXPLANATION:

Let R represent Ronald’s present age. Let M represent Miley’s present age. Three years from now, Ronald and Miley will be R+3 and M+3 years old, respectively.

Your assertion “Three years from now, Ron’s age will be 2 times that of Miley's” can be written as

R + 3 = 2*(M + 3)

Similarly, your assertion “Three years ago, Ron's age was 3 times that of Miley's” can be written as

R - 3 = 3*(M-3)

We can add the left side of these equations together, and also the right side of these equations together, and obtain a new equation …

R + 3 + R - 3 = 2*(M + 3) + 3*(M - 3) = 2M + 6 + 3M - 9 = 5M - 3

This can be simplified to

2R = 5M - 3

We can divide both sides of the last equation by 2, and obtain ..

(2/2) * R = (5/2) * M - 3/2, or R = (5/2) * M - 3/2.

Now we can “plug in” the last equation into either of our first two equations of this post, and solve for M.

Using the first equation, we have

(5/2) * M - 3/2 + 3 = 2 *(M + 3) = 2M + 6

We now have

(5/2) * M + 3/2 = 2M + 6

The left side of this equation can be rewritten as

(5M + 3) / 2, so we obtain

(5M + 3) / 2 = 2M + 6

Multiplying both sides by 2, we have

5M + 3 = 4M + 12

Subtracting 4M and 3 from both sides, we obtain

M = 9

Miley’s present age is 9.

plss give brainliest

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parallel when a=2

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GarryVolchara [31]

Answer:

Divide

Step-by-step explanation:

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3 years ago