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Anna007 [38]
3 years ago
13

Find the range of the function for the domain(-4,-2,0, 1.5,4).f(x) = 5x²+ 4​

Computers and Technology
1 answer:
Masja [62]3 years ago
4 0
<h2>Hello!</h2>

The answer is:

The range or output for the given domain is:

(84,24,4,15.25,84)

<h2>Why?</h2>

To find the range (output) for the given domain (inputs) we need to evaluate the given function with the given inputs or "x" values.

So, evaluating, we have:

- Range with "x" equal to -4:

f(x)=5x^{2} +4\\\\f(-4)=5*(-4)^{2} +4=5*16+4=84

- Range with "x" equal to -2:

f(x)=5x^{2} +4\\\\f(-2)=5*(-2)^{2} +4=4*5+4=24

- Range with "x" equal to 0:

f(x)=5x^{2} +4\\\\f(-2)=5*(0)^{2} +4=0+4=4

- Range with "x" equal to 1.5:

f(x)=5x^{2} +4\\\\f(-2)=5*(1.5)^{2} +4=11.25+4=15.25

- Range with "x" equal to 4:

f(x)=5x^{2} +4\\\\f(-2)=5*(4)^{2} +4=80+4=84

Hence, the range or output for the given domain is:

(84,24,4,15.25,84)

Have a nice day!

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3 years ago
Write a procedural programming loop.. Your loop should start variable n with a value of 10 and count down to zero. The loop shou
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Answer:

//Here is the for loop in C.

for(n=10;n>0;n--)

{

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}

Explanation:

Since C is a procedural programming language.Here if a loop that starts with n=10; It will run till n becomes 0. When n reaches to 0 then loop terminates otherwise it  print the count of n.

// here is code in C++.

#include <bits/stdc++.h>

using namespace std;

// main function

int main()

{  // variables

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// when n==0 then loop terminates

for(n=10;n>0;n--)

{

   cout<<"count ="<<n<<endl;

}

return 0;

}

Output:

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count =2

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Answer:

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Explanation:

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