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timama [110]
3 years ago
15

For this exercise, we are going to take a look at an alternate Calculator class, but this one is broken. There are several scope

issues in the calculator class that are preventing it from running. Your task is to fix the Calculator class so that it runs and prints out the correct results. The CalculatorTester is completed and should function correctly once you fix the Calculator class.
public class Calculator {
private int total;
private int value;
public Calculator(int startingValue){
int total = startingValue;
value = 0;
}
public int add(int value){
int total = total + value;
return total;
}
/**
* Adds the instance variable value to the total
*/
public int add(){
int total += value;
return total;
}
public int multiple(int value){
int total *= value;
return total;
}
public void setValue(int value){
value = value;
}
public int getValue(){
return value;
}
}
Computers and Technology
1 answer:
vekshin13 years ago
7 0

Answer:

public class Calculator {

   private int total;

   private int value;

   

   public Calculator(int startingValue){

       // no need to create a new total variable here, we need to set to the our instance total variable

       total = startingValue;

       value = 0;

   }

   public int add(int value){

       //same here, no need to create a new total variable. We need to add the value to the instance total variable

       total = total + value;

       return total;

   }

   /**

   * Adds the instance variable value to the total

   */

   public int add(){

       // no need to create a new total variable. We need to add the value to the instance total variable

       total += value;

       return total;

   }

   public int multiple(int value){

       // no need to create a new total variable. We need to multiply the instance total variable by value.

       total *= value;

       return total;

   }

   //We need to specify which value refers to which variable. Otherwise, there will be confusion. Since you declare the parameter as value, you need to put this keyword before the instance variable so that it will be distinguishable by the compiler.

   public void setValue(int value){

       this.value = value;

   }

   public int getValue(){

       return value;

   }

}

Explanation:

I fixed the errors. You may see them as comments in the code

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1. Scrieţi un program care citeşte un număr natural n şi determină produsul cifrelor impare ale lui n. De exemplu, pentru n = 23
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Answer:

1.  

num1 = input("Enter the value of n")  

n = int(num1)  

def calc(n):  

Lst = []  

while n > 0:  

remainder = n % 10  

Lst.append(remainder)  

quotient = int(n / 10)  

n = quotient  

i = len(Lst) - 1  

sum = 1  

for i in range(0, len(Lst)):  

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sum *=Lst[i];  

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\ r2

num=input("Enter the value of n")

arr=[12,-12,13,15,-34,-35,35,42]

def div7positive():

  sum = 0

  m = 0

  i = 0

  while m <= 7:

      if(arr[i]>=0 and arr[i]%7 == 0):

          sum +=arr[i]

      i = i + 1

      m += 1

       

   

  print("sum of number divisible by 7 and positive is", +sum);

div7positive()

\ r

\ r3.Write an algorithm that reads a natural number n and calculates the sum:

\ rS = 1 / (1 * 2) + 1 / (2 * 3) + 1 / (3 * 4) +… + 1 / ((n-1) * n)

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num=input("Enter the value of n")

def sumseries():

  sum = 0

  m= 0

  while m <= 7:

      sum +=1/((int(num)-1)*int(num))

      m += 1

  print("sum of series is", +sum)

sumseries()

\ R4. Read a natural number n. Calculate the sum of its own divisors n. For example, for n = 12, the sum of its own divisors is 2 + 3 + 4 + 6 = 15

num=input("Enter the value of n")

def sumdivisors():

  sum = 0

  m= 2

  while m <= int(num):

      if int(num) % m == 0:

          sum += m

      m += 1

  print("sum of divisors is", +sum)

sumdivisors()\ r

\ R5. We read a natural number n and then whole numbers. Calculate and display the sum of the natural numbers between 10 and 100. For example, if n = 5 and then read 30, –2, 14, 200, 122, then the sum will be 44 (that is, 30 + 14).

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Lst = []  

num=input("Enter the value of n")

i = 0

while i<= int(num):

  num1=input("Enter the element of array")

  Lst.append(int(num1));

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def numbet0and100():

  sum = 0

  m= 0

  while m <= int(num):

      if Lst[m] <= 100 or Lst[m] >=0:

          sum += Lst[m]

      m += 1

  print("sum of numbers between 0 and 100 is", +sum)

numbet0and100()

\ R6. A natural number n of maximum 4 digits is read. How many digits are in all numbers from 1 to n? For example, for n = 14 there are 19 digits, and for n = 9 there are 9 digits.

\ r

num = input("Enter the value of n")

n = int(num)

print(“sum as required is:” (n -9) + n)  

 

\ R7. Read the natural numbers n and S, where n can be 2, 3, 4 or 5. Show all the numbers of n digits that have the numbers in strictly ascending order, and the sum of the digits is S. For example, for n = 2 and S = 10, 19, 28, 37, 46 will be displayed.

num = input("Enter the value of n")

n = int(num)

Lst = []

def calc(n):

  i = 1

  total = pow(10,n)

  while i <= total:

      j = i

      while j > 0:

          remainder = j % 10  

          Lst.append(remainder)

          quotient = int(j / 10)

          if quotient > 0:

              j = quotient

          else:

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              sum = 0

              while length >= 0:

                  sum += Lst[length]

                  length = length - 1

              if sum == pow(10,n):

                  print(j)

              k = len(Lst)

              del Lst[0:k]

      i = i + 1

  return(0)

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\ R8. We consider the row 1, 1, 2, 3, 5, 8, 13, ... in which the first two terms are 1, and any other term is obtained from the sum of the preceding two. Write an algorithm that reads a natural number n and displays the first n terms of this string. For example, for n = 6, 1, 1, 2, 3, 5, 8 will be displayed.

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nterm = int(input("What number of terms do you want?"))

a, b = 0, 1

totalcount = 0

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num1 = input("Enter the value of n")

num3 = input("Enter the value of n")

n = int(num1)

num2 = int(num3)

def calc(n):

  Lst = []

  while n > 0:

      remainder = n % 10  

      Lst.append(remainder)

      quotient = int(n / 10)

      n = quotient

       

  i = len(Lst) - 1

  sum = 0

  while i >= 0:

      sum += Lst[i]* Lst[i]

      i = i - 1

  return(sum)

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  Lst = []

  while num2 > 0:

      remainder = num2 % 10  

      Lst.append(remainder)

      quotient = int(num2 / 10)

      num2 = quotient

       

  i = len(Lst) - 1

  sum = 0

  while i >= 0:

      sum = Lst[i] + Lst[i]

      i = i - 1

  return(sum)

a = calc(n)

b = calc1(num2)

if a == b:

  print("yes")

else:

  print("No")

\ r

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\ r

num1 = input("Enter the value of n")

n = int(num1)

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  Lst = []

  while n > 0:

      remainder = n % 10  

      Lst.append(remainder)

      print( remainder)

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Explanation:

Please check answer.  

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