Answer:
15.87% probability that a randomly selected individual will be between 185 and 190 pounds
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
What is the probability that a randomly selected individual will be between 185 and 190 pounds?
This probability is the pvalue of Z when X = 190 subtracted by the pvalue of Z when X = 185. So
X = 190
has a pvalue of 0.8944
X = 185
has a pvalue of 0.7357
0.8944 - 0.7357 = 0.1587
15.87% probability that a randomly selected individual will be between 185 and 190 pounds
Answer:
math duh
Step-by-step explanation:
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Answer:
Independent
Step-by-step explanation:
Barbie selecting a coin and putting it back in has no effect on Darren selecting a coin from the jar, as the numbers of each coin never changed. So, both events are independent with neither relying on the other.
23/40
3/8 + 1/5 = 15/40 + 8/40 = 23/40
i don't know if that can be simplified <span />
Answer:
2 of the 1/3 Bananas and 5 of the 1/4 strawberries
Step-by-step explanation:
two of the 1/3 bananas can complete the pound of grapes and one of the 1/4 of strawberries can complete the pound of apples so then u got 4 more of 1/4 and u got three pounds exact