PLEASE HELP !! ILL GIVE 40 POINTS ; PLUS BRAINLIEST !! DONT SKIP ANSWER.
2 answers:
<h3>Option C is Correct:</h3>
- Angle RQN and angle MNQ are alternate interior angles.
● <u>Alternate interior angles are always equal</u>.
<h3>How are other options incorrect?</h3>- Angles given in <u>option A</u> are forming <u>linear pair</u>.
- Angles given in <u>option B</u> are too forming a <u>linear pair.</u>
- Angles given in <u>option D</u> are <u>corresponding angles.</u>
You might be interested in
Answer:
The function is y = 40 * 2^(x/2)
The graph is in the image attached
Step-by-step explanation:
The function that models this growth is an exponencial function, that can be described with the following equation:
y = a * b^(x/n)
Where a is the inicial value, b is the rate of growth, x is the time and n is the relation between the time and the rate (the rate occurs for every two hours, so n = 2).
Then, using a = 40, r = 2 and n = 2, we have:
y = 40 * 2^(x/2)
If we plot this function, we have the graph shown in the image attached,
It is an exponencial graph, where the value of y increases very fast in relation to the increase of x.
9514 1404 393
Answer:
(i) 55.59 km/h
(ii) 3600 nautical miles ≈ 6670.8 km
(iii) 30°N 29.3°E
Step-by-step explanation:
(i) The speed in km/h requires a units conversion.
(30 kt/h)(1.853 km/kt) = 55.59 km/h
__
(ii) Here, we assume we're interested in the <em>distance traveled</em>. If the course is "due east", we presume that means it follows the 30° latitude line, so is not the shortest route between A and B. That is, the distance from A to B will be different from the distance traveled. (The shortest route from A to B is along a great circle.)
distance = speed × time
distance = (30 kt/h)(120 h) = 3600 nautical miles
= (55.59 km/h)(120 h) = 6670.8 km
__
(iii) The radius of the 30° latitude line is ...
(6370 km)(cos(30°)) = 3185√3 km ≈ 5516.58 km
The relationship between arc length (s) and central angle (α) is ...
s = rα
So, the change in the vessel's longitude is ...
α = (6670.8 km)/(5516.58 km) ≈ 1.20923 radians ≈ 69.28°
Then town B has longitude ...
40°W -69.3° = -29.3°W = 29.3°E
The position of town B is about 30°N 29.3°E.
_____
<em>Additional comment</em>
The route supposedly taken by this sea vessel is from the middle of the North Atlantic to a town in northern Egypt, through the northern Sahara desert. The eastern end point is shown in the attachment.
Some spherical trigonometry is involved if you want to find the end point of the great-circle route of the same length.
