Answer: Maybe if you knew the def's you could answer it.
Initial Decay – Bacteria located mainly in the lower intestine begin decomposition, giving a greenish color to the lower abdomen. Stage 2: Putrefaction – Bacteria grow throughout the body, releasing gases, including cadaverine, which in turn bloat the body and cause unpleasant odor.
putrefaction
the process of decay or rotting in a body or other organic matter.
Black putrefaction occurs, which is when noxious odors are released from the body and the parts of the body undergo a black discoloration. 2 weeks: The abdomen is bloated; internal gas pressure nears maximum capacity. 3 weeks: Tissues have softened. Organs and cavities are bursting.
Fermentation occurring in putrefaction and apparently in the digestion of herbivorous mammals in which butyric acid is produced by certain chiefly anaerobic bacteria acting upon various organic substances (such as lactic acid or butter)
A dry body will not decompose efficiently. Moisture helps the growth of microorganisms that decompose the organic matter, but too much moisture could lead to anaerobic conditions slowing down the decomposition process
It would be C, The internal structure of cells withing the body. Microscopes are designed to look at cells, as the magnification is at that level.
Genetic diversity
Explanation:
Sexual reproductions, mutation, and crossing-over generates a wide range of genetic diversity within a population.
- Sexual reproduction is a type of reproduction in which gametes fuses to produce a fertile and viable offspring.
- Mutation is the process of altering genetic sequences in population to production new breeds called mutants.
- Crossing-over is the exchange of chromosomes between two homologous pairs.
All these processes ensures that a pool of diverse gene exists within a population in order give competitive and adaptability advantage to organisms.
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Answer:
The first three look like clear quartz then the last two might be obsidian
Explanation:
Tried my best hope this helps!
Hydrogen bonds exists between the DNA strand and its complementary strand such that; there are two hydrogen bonds between every A and T, and three between every C and G.
Therefore; in this case there will be (2 ×3 ) +(3×3) = 15 hydrogen bonds for the above strand. this is because Adenine binds to Thyamine with two bonds (3 pairs) and Guanine binds to Cytosine with three bonds (3 pairs).