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Contact [7]
3 years ago
9

To find the square root of a number, you must divide the number by 2. True False

Mathematics
1 answer:
Kaylis [27]3 years ago
5 0
To find the square root of a number you would have to divide it by 2
So yes the answer is true
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Can I get help with finding the Fourier cosine series of F(x) = x - x^2
trapecia [35]
Assuming you want the cosine series expansion over an arbitrary symmetric interval [-L,L], L\neq0, the cosine series is given by

f_C(x)=\dfrac{a_0}2+\displaystyle\sum_{n\ge1}a_n\cos nx

You have

a_0=\displaystyle\frac1L\int_{-L}^Lf(x)\,\mathrm dx
a_0=\dfrac1L\left(\dfrac{x^2}2-\dfrac{x^3}3\right)\bigg|_{x=-L}^{x=L}
a_0=\dfrac1L\left(\left(\dfrac{L^2}2-\dfrac{L^3}3\right)-\left(\dfrac{(-L)^2}2-\dfrac{(-L)^3}3\right)\right)
a_0=-\dfrac{2L^2}3

a_n=\displaystyle\frac1L\int_{-L}^Lf(x)\cos nx\,\mathrm dx

Two successive rounds of integration by parts (I leave the details to you) gives an antiderivative of

\displaystyle\int(x-x^2)\cos nx\,\mathrm dx=\frac{(1-2x)\cos nx}{n^2}-\dfrac{(2+n^2x-n^2x^2)\sin nx}{n^3}

and so

a_n=-\dfrac{4L\cos nL}{n^2}+\dfrac{(4-2n^2L^2)\sin nL}{n^3}

So the cosine series for f(x) periodic over an interval [-L,L] is

f_C(x)=-\dfrac{L^2}3+\displaystyle\sum_{n\ge1}\left(-\dfrac{4L\cos nL}{n^2L}+\dfrac{(4-2n^2L^2)\sin nL}{n^3L}\right)\cos nx
4 0
3 years ago
At the beginning of the day, stock XYZ opened at $6.12. At the end of the day, it closed at $6.88. What is the rate of change of
Natalija [7]

Answer:

C is the correct option.

Step-by-step explanation:

We have been given that

stock XYZ opened at $6.12 and it closed at $6.88 and we have find the rate of change of stock.

Change in the value =| Initial - final |

Change in the value = |6.12-6.88|

Change in the value = 0.76

Hence, the rate of change of stock is given by

\frac{\text{Change in value}}{\text{initial value}}\times100\\\\=\frac{0.76}{6.12}\times100\\\\=12.4\%

C is the correct option.


7 0
2 years ago
Please help! 12 points
Ivahew [28]

Answer:

Step-by-step explanation:

sin2x = 2sinx*cosx

         = 2\sqrt{sin^{2}x } * cosx

         = 2\sqrt{(1-cos^{2}x } * cosx

         = 2  \sqrt{1-\frac{3}{5} ^{2} } *\frac{3}{5}

         = \frac{8}{5}  * \frac{3}{5}  

         = 24/25        

8 0
3 years ago
Vanessa and Zack are playing a game where the player with the lower score wins.
dezoksy [38]
What is the question
3 0
3 years ago
Read 2 more answers
Which facts could be applied to simplify this expression? Select three options.
kumpel [21]

Answer:

A, B, and D

Step-by-step explanation:

To subtract like terms, you're supposed to subtract the coefficients, so <u><em>Option 1 is correct</em></u>. The statement like terms are terms that contain the same variable, raised to the same power, is true, so <u><em>Option 2 is correct</em></u>. The simplified expression is -4 - 3y + 3z, so Option 3 is wrong and <u><em>Option 4 is correct</em></u>. Option 5, -(-x) = -x is wrong, so Option 5 is not correct. Therefore, the answers are Options 1, 2, and 4 (or A, B, and D).

Hope this helps! I got it right on Edgen.

3 0
3 years ago
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