From an aeroplane vertically above a straight horizontal plane, the angles of depression of two consecutive kilometres stones on the opposite sides of the aeroplane are found to be "alpha" and "beta". Show that the height of the aeroplane is: (tan alpha * tan beta)/(tan alpha + tan beta).
1 answer:
You have to build the triangles. They are such that: h is the common height x is the horizontal distance from the plane to one stone Beta is the angle between x and the hypotenuse Then in this triangle: tan(beta) = h / x ......(1) 1 - x is the horizontal distance from the plane to the other stone alfa is the angle between 1 - x and h Then, in this triangle: tan (alfa) = h / [1 -x ] ...... (2) from (1) , x = h / tan(beta) Substitute this value in (2) tan(alfa) = h / { [ 1 - h / tan(beta)] } => { [ 1 - h / tan(beta) ] } tan(alfa) = h [tan(beta) - h] tan(alfa) = h*tan(beta) tan(beta)tan(alfa) - htan(alfa) = htan(beta) h [tan(alfa) + tan(beta) ] = tan(beta) tan (alfa)h = tan(beta)*tan(alfa) / (t an(alfa) + tan(beta) )
You might be interested in
Answer:
t pounds = 3.5 (or just t = 3.5c)
Step-by-step explanation:
2 pounds of tomatos for 7$ means that one pound of tomatos for 3.5$. Therefore, t pounds = 3.5 c
You have a fifty percent chance of heads or tails, so the probability of it landing on the same side twice is 25 percent.
Answer:
672.12
Step-by-step explanation:
He spent 3/6 hours more or 30 minutes more
Y = -5x + 28 will be parallel to your equation because it has the same coefficient but will also pass through (3, 13)