Answer:
Multiply the number of cans by the volume of each: 12,000 oz.
Step-by-step explanation:
You find the total volume of more than one can by adding the volumes of the cans involved.
For 2 cans, the volume would be ...
12 oz + 12 oz = 24 oz
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When you consider adding numbers more than a couple of times, you start looking for ways to simplify the effort. Multiplication was invented for that purpose. Here, multiplying the volume of 1 can by 1000 is the same as adding the volumes of 1000 cans.
For 1000 cans with volume of 12 oz each, the volume of the total is ...
1000 × 12 oz = 12,000 oz.
<span>Multiply one of the equations so that both equations share a common complementary coefficient.
In order to solve using the elimination method, you need to have a matching coefficient that will cancel out a variable when you add the equations together. For the 2 equations given, you have a huge number of choices. I'll just mention a few of them.
You can multiply the 1st equation by -2/5 to allow cancelling the a term.
You can multiply the 1st equation by 5/3 to allow cancelling the b term.
You can multiply the 2nd equation by -2.5 to allow cancelling the a term.
You can multiply the 2nd equation by 3/5 to allow cancelling the b term.
You can even multiply both equations.
For instance, multiply the 1st equation by 5 and the second by 3. And in fact, let's do that.
5a + 3b = –9
2a – 5b = –16
5*(5a + 3b = -9) = 25a + 15b = -45
3*(2a - 5b = -16) = 6a - 15b = -48
Then add the equations
25a + 15b = -45
6a - 15b = -48
=
31a = -93
a = -3
And then plug in the discovered value of a into one of the original equations and solve for b.</span>
Answer:
70% in favor of building a new playground
<em>3500 (</em><em>in favor</em><em>) + 1500 (</em><em>against it</em><em>) = 5000 (</em><em>total number votes</em><em>)</em>
<em />
<em>3500 (</em><em>in favor</em><em>) 1500 (</em><em>against it</em><em>)</em>
<em> ------------------- = 0.7 / 70% ------------------- =0.3 / 30%</em>
<em>5000 (</em><em>total</em><em>) 5000 (</em><em>total</em><em>) </em>
Yes, it will always be a rational number. I'll expound on this by defining what a rational number is. It is any number that can be expressed as a fraction. Otherwise, it is called an irrational number with a non-terminating decimal expansion. So, although 1/3 has a non-terminating decimal expansion because it is equal to 0.33333333...., it is still a rational number because it can be expressed into a fraction.
Answer:
ight
Step-by-step explanation:
I'll think bout it.
I may join, but I won't be on that much.
