To find the mean all you have to do is add all the numbers...
you should get -30
and divide by a number of numbers, there are 6
so -30/6 is -5
Find
where
<span>So to find the left sided limit, you need to plug in -8, into x+9
and to find the right sided limit, you need to plug in -8, into -7-x.
</span>
<span>If the two sides of the limit are no equivalent, then </span>
Since both sides are equal to 1, the limit is 1.
Answer:
5 square units.
Step-by-step explanation:
See the attached graph where D, E, F, and G points are plotted.
So, in trapezium DEFG, the parallel sides are GF and DE.
Now, it is clear from the graph that, the length of segment GF = (3 - 1) = 2 units and the length of line segment DE = (3 - 0) = 3 units.
Now, the altitude of the trapezium is GD with length (4 - 2) = 2 units.
Therefore, the area of the trapezium will be given by
⇒ square units. (Answer)
Step-by-step explanation:
tc gxigxixigxig✌✌✌✌❤dsgggzoigsigsigzziigzigzigsigsigzufUfz
Answer:
(a) 12.96 ft²
(b) 21.5 in²
Step-by-step explanation:
(a) For the first diagram
Area of the shaded region (A) = Area of Tripezium- area of circle
A = [1/2(a+b)h]-[πr²]............... Equation 1
Where a and b are the parallel side of the tripezium respectively, h = height of the tripezium, r = radius of the circle.
From the diagram,
Given: a = 15 ft, b = 6 ft, h = 12 ft, r = h/2 = 12/2 = 6 ft.
Constant: π = 3.14
Substitute these values into equation 1
A = [12(15+6)/2]-(3.14×6²)
A = 126-113.04
A = 12.96 ft²
(b) For the second diagram,
Area of the shaded region (A') = Area of square- area of circle
A' = (L²)-(πr²)............. Equation 2
Where L = lenght of one side of the square, r = radius of the circle
From the diagram,
Given: L = 2r = (2×5) = 10 in, r = 5 in
Substitute these values into equation 2
A' = (10²)-(3.14×5²)
A' = 100-78.5
A = 21.5 in²