I believe the answer is 1.1112007e+16 because 14^5=537824 and 14^-9= 4.8400258e-11. You divide both numbers and get 1.1112007e+16
Hello!
As you can see, C is the cost of each uniform. This would give us the equation below, if each uniform was $60.
60=40n+260/n
Let's multiply both sides by n.
60n=40n+260
Now, let's subtract 40n from both sides.
20n=260
We divide both sides by 20.
n=13
Therefore, 13 uniforms were purchased.
I hope this helps!
So this is a BIDMAS question so first you do what’s in the brackets so you have (1-9x1-4) and you have to do the multiplication first out of that to get (1-9-4) which is -12 so then you have overall 36 / -12 + 1 + 2 so you have to do the division first so do 36/-12 to get -3 and you have -3 + 1 + 2 which is 0 so your answer is 0.
To solve this problem, let us say that:
money invested in stock A = A
money invested in stock B = B
money invested in stock C = C
The given problem states that:
C = A * (1 / 4) = 0.25 A
B = A * (1 / 2) = 0.50 A
It was stated that we only have $16,000 to invest.
Therefore:
A + B + C = 16,000
Substituting values of C and B in terms of A:
A + 0.50 A + 0.25 A = 16,000
1.75 A = 16,000
A = $9,142.86
So C and B is:
C = 0.25 (9142.86)
C = $2285.71
B = 0.50 (9142.86)
B = $4571.43
Answer:
9 x 7.5
Step-by-step explanation:
Just 9 x 7 = 63 > 55
8 x 5 = 40 < 55
5 x 10 = 50 < 55
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