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ziro4ka [17]
3 years ago
5

A newsletter publisher believes that less than 49% of their readers own a laptop. For marketing purposes, a potential advertiser

wants to confirm this claim. After performing a test at the 0.10 level of significance, the advertiser decides to reject the null hypothesis. What is the conclusion regarding the publisher's claim
Mathematics
1 answer:
Zepler [3.9K]3 years ago
5 0

Answer:

The answer is "At the 0,10 level, there should be enough proof that the percentage is below 49%"

Step-by-step explanation:

Null and alternative hypothesis:

H_0 :P \geq 0.49\\\\H_1:P

Significance level: \alpha = 0.10

It is decided that the null hypothesis at the defined meaning level is rejected.

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A school has 1800 students 55 %of the students of girls. how many boys are in the school?​
Katena32 [7]

Answer:

810 boys

Step-by-step explanation:

1800 students and 55% are girls.

100%-55%=45%

1800*0.45 = 810

1800*0.55 = 990

So there are 990 girls and 810 boys.

Hope this helps :)

3 0
3 years ago
Anna is going to invest in an account paying an interest rate of 5.1% compounded
Ronch [10]

Answer:

it’s 23000    

Step-by-step explanation:

3 0
3 years ago
A bag contains 10 marbles: 2 are green, 6 are red, and 2 are blue. Jessica chooses a marble at random, and without putting it ba
Alexxandr [17]
P(green)=2/10=1/5
P(red, no replacement)=6/9=2/3

So, 1/5(2/3)=2/15
3 0
4 years ago
A terminating decimal is a decimal that​
dalvyx [7]

Answer:A terminating decimal is a decimal that ends. It's a decimal with a finite number of digits

Step-by-step explanation:

3 0
3 years ago
A box contains 16 ​transistors, 5 of which are defective. if 5 are selected at​ random, find the probability that
ExtremeBDS [4]
Part (a): All are defective
Only one way of selecting the 5 defective transistors:

Number of ways of selections available = 6C5 = 16!/[5!*(15-5)!] = 4368

Probability they are all defective = Number of ways of selecting 5 defectives/Total number of ways possible = 1/4368 ≈ 0.000229

Part (b): None are defective
Total number of non defectives = 16 -5 = 11
Number of ways of selecting 5 non defective = 11C5 = 462 ways
Total number of ways possible = 16C5 = 4368
Probability of selecting 5 non defectives = 462/4368 = 11/104 ≈ 0.1058


5 0
4 years ago
Read 2 more answers
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