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4 years ago

11

Round the number to the thousandths place. 64,672.318498

1 answer:

lesya [120]4 years ago

4 0

The correct answer would be d. 64,672.318.

This is because the thousandths place ends at the 8, and because the number following that (a 4) is less than 5, you should keep the 8 instead of rounding up.

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What are all the real zeros

xeze [42]

For this case we have a function of the form $y = f (x)$ , where $f (x) = (x-12) ^ 3-10$

To find the real zeros we must equal zero and clear the variable "x".

$(x-12) ^ 3-10 = 0$

We add 10 to both sides of the equation

$(x-12) ^ 3-10 + 10 = 10\\(x-12) ^ 3 = 10$

We apply cube root to both sides of the equation:

$\sqrt[3]{(x-12)^3} = \sqrt[3] {10}\\x-12 = \sqrt[3] {10}$

We add 12 to both sides of the equation:

$x-12 + 12 = \sqrt[3] {10} +12\\x = \sqrt[3] {10} +12$

Answer:

Option D

5 0

3 years ago

Un comerciante de algodón de azúcar gana 40 cm por cada algodón vendido pero si no lo logra venderlo pierde 50 céntimos. un día

gayaneshka [121]

Answer:

He fails to sell that day 10 cottons.

Step-by-step explanation:

We are given that a cotton candy merchant earns 40 cents for each cotton sold, but if he cannot sell it he loses 50 cents.

One day when he made 120 cottons, he made a profit of 39 soles.

Let the number of cottons merchant is able to sold be 'x' and the number of cottons merchant is not able to sold be 'y'.

So, according to the question;

The first condition states that he made 120 cottons on one day, that is;

x + y = 120

x = 120 - y ---------------------- [Equation 1]

The second condition states that merchant earns 40 cents for each cotton sold, but if he cannot sell it he loses 50 cents and due to which he made a profit of 30 soles, that is;

$0.40x - 0.50y=39$

$40x - 50y=3900$

$40(120-y) - 50y=3900$

$4800-40y - 50y=3900$

$90y=4800-3900$

$90 y = 900$

$y=\frac{900}{90}=10$

This means that the merchant is not able to sell 10 cottons.

4 0

3 years ago

Can someone please help me?

ss7ja [257]

For each square root, you can simplify the expression under the root as

$3\sqrt{98xy}=3\sqrt{2\cdot7^2xy}=3\cdot7\sqrt{2xy}=21\sqrt{2xy}$

$\sqrt{108y}=\sqrt{2^2\cdot3^3xy}=2\cdot3\sqrt{3xy}=6\sqrt{3xy}$

$2\sqrt{75xy}=2\sqrt{3\cdot5^2xy}=2\cdot5\sqrt{3xy}=10\sqrt{3xy}$

So we have

$3\sqrt{98xy}-\sqrt{108xy}+2\sqrt{75xy}=21\sqrt{2xy}-6\sqrt{3xy}+10\sqrt{3xy}$

$=21\sqrt{2xy}+4\sqrt{3xy}$

This means [1] = 4 and [2] = $3xy$ .

7 0

3 years ago

Divide 6x^3 + 1 - 14x by 3x +6 solve it

Lena [83]

Answer:

$2 {x}^{2} - 4x + \frac{10}{3} - \frac{19}{3x + 6}$

3 0

4 years ago

Can someone explain this?

artcher [175]

Answer:

13

-2*3-15/(-5)4-(-7)

Step-by-step explanation:

5 0

4 years ago