Graph the line passing through (−2,5) whose slope is m=1/5
2 answers:
Answer:
In order to graph the line, you need to first find the y-intercept (aka 'b').
Equation: y=mx+b
Given the two points and slope, we can plug in and find for b
5 = 1/5(-2) + b
5 = -2/5 + b
b = 5 + 2/5
b = 27/5 or 5.4
So your final equation will be: y=1/5x+27/5
Lastly you just need to plot the 'b = 5.4' on the y-axis and place the slope as 1 over 5.
Hello there! :)
Given:
x-coordinate of point = -2
y-coordinate of point = 5
Slope, or "m" = 1/5
Substitute in these values into slope-intercept formula (y = mx+b)
5 = 1/5(-2) + b
5 = -2/5 + b
25/5 = -2/5 + b
27/5 = b
Rewrite the equation:
y = 1/5x + 27/5
Graph the equation using a graphing utility:
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