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lakkis [162]
3 years ago
6

Simplify.

Mathematics
2 answers:
tresset_1 [31]3 years ago
6 0
Answer is B
<span>6x5−12x4+9x3</span>
guajiro [1.7K]3 years ago
4 0

Answer:

i took this test and I can confirm that answer B is correct: 6x^5-12x^4+9x^3

Step-by-step explanation:

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The graph shows the distance Arlene ran on Saturday preparing for a marathon. What is the rate of change and what does it repres
andreev551 [17]

Answer:

Rate of change = 6 miles per hour

Step-by-step explanation:

Rate of change of the line is represented by the slope of the line.

Formula to get the rate of change is,

m = \frac{\triangle y}{\triangle x}

From the graph attached,

Given straight line is passing through two points (2, 12) and (4, 24).

Rate of change = \frac{y_2-y_2}{x_2-x_1}

                          = \frac{24-12}{4-2}

                          = 6

Rate of change of the line = 6 miles per hour

Therefore, rate of change of the graph will define the speed of Arlene.

3 0
3 years ago
PLSSS HELP IF YOU TURLY KNOW
mylen [45]

Answer:

x = 5

Step-by-step explanation:

(3-6x)/3 = -11

first multiple both sides by 3

3 - 6x = -33

then subtract 3 from both sides

-6x = -30

then divide by 6

x = 5

8 0
3 years ago
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Canh square roots be rational numbers ?
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When the square root of a number is a whole number, this number is called a perfect square. ... Not all square roots are whole numbers. Many square roots are irrational numbers, meaning there is no rational number equivalent
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3 years ago
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You like anime or nah??
gladu [14]

Answer: I love anime

Step-by-step explanation:

3 0
3 years ago
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Need help fast plz for my pre calc exam
bezimeni [28]

Answer:

<em>h = 8.54 units</em>

Step-by-step explanation:

<u>The Law of Cosines </u>

It relates the length of the sides of a triangle with one of its internal angles.

Let a,b, and c be the length of the sides of a given triangle, and x the included angle between sides a and b, then the following relation applies:

c^2=a^2+b^2-2ab\cos x

Since we know the values of all three side lengths, we solve the equation for x:

\displaystyle \cos x=\frac{a^2+b^2-c^2}{2ab}

For the triangle ABC in the image, a=10, b=15, c=13, thus:

\displaystyle \cos A=\frac{10^2+15^2-13^2}{2*10*15}

\displaystyle \cos A=\frac{156}{300}

\displaystyle \cos A=0.52

Thus, A = 58.67°

For the right triangle of height h and hypotenuse 10, we use the sine ratio:

\displaystyle \sin 58.67^\circ=\frac{h}{10}

Solving for h:

h = 10\sin 58.67^\circ

h = 8.54 units

6 0
3 years ago
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