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ololo11 [35]
3 years ago
10

Find the missing values to make the statement true.

Mathematics
2 answers:
Hatshy [7]3 years ago
7 0

Answer:yes

Step-by-step explanation:

omeli [17]3 years ago
7 0
Yeah , you did . what kinda math is this?
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Two word phrases for each expression t+32
mixas84 [53]
A number plus 32.
The sum of a number and 32.
8 0
3 years ago
Identify the translation of the figure with the vertices F(4,0), G(1,3), H(2,6) and I(4,2), along the vector ⟨−4,−4⟩. HELP PLEAS
mr Goodwill [35]

Answer:

  the last choice shown here: F'(0, -4), G'(-3, -1), H'(-2, 2), I'(0, -2)

Step-by-step explanation:

The translation vector tells you that the new coordinates are found by adding -4 to each of the old coordinates. When you realize that the answer choices differ in their values for H' and I', you can conclude that you only need to find one of those to determine the correct answer.

  H' = H + (-4, -4) = (2-4, 6-4) = (-2, 2) . . . corresponds to the last choice shown

_____

When you subtract 4 from each of the coordinates of the other points, you find they also match the last answer selection.

4 0
3 years ago
This isn’t too difficult of questions and I am pretty sure I know the answers but I just want to make sure. Can someone please h
Shkiper50 [21]
Q2 Anwser
Exact Form:
28/15
Decimal Form:
1.86
Mixed Number Form:
1 13/15
5 0
3 years ago
What is the radius of a hemisphere with a volume of 6496 (cm to the third power) to the nearest tenth of a centimeter?
professor190 [17]

Answer:

14.6cm

Step-by-step explanation:

The volume of a hemisphere is 2/3 × π × r³ → 6496 = 2/3 × π × r³. You can divide both sides by 2/3π to get r³ on its own → 3103.611531 = r³. To find r, cube root both sides → r = ∛3103.611531 = 14.5835... ≈ 14.6cm.

Hope this helps!

5 0
3 years ago
Read 2 more answers
What is the solution of the system of equations?<br> 3x+2y+z=7<br> 5x+5y+4z=3<br> 3x+2y+3z=1
Umnica [9.8K]
The answer is x = 4
y = -1
z = -3

<span>3x+2y+z=7
5x+5y+4z=3
3x+2y+3z=1
________
Let's take the first and the third equation, multiply the first one by (-1) and sum them up:
</span>3x+2y+z=7
3x+2y+3z=1
____
-3x-2y-z=-7
3x+2y+3z=1
____
2z = -6
z = -6/2
z = -3


Substitute z in all equations:
3x+2y+z=7
5x+5y+4z=3
3x+2y+3z=1
______
3x + 2y - 3 = 7
5x + 5y - 12 = 3
3x + 2y - 9 = 1
______
3x + 2y = 10
5x + 5y = 15
3x + 2y = 10

The first and the third equations are the same, so one can be excluded:
3x + 2y = 10
5x + 5y = 15

Multiply the first equation by -5 and the second equation by 2 and sum them up:
-15x - 10y = -50
10x + 10y = 30
_________
-5x = -20
x = -20/-5
x = 4

Substitute x:
3x + 2y = 10
12 + 2y = 10
2y = 10 - 12
2y = -2
y = -2/2
y = -1
3 0
3 years ago
Read 2 more answers
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