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Verizon [17]
3 years ago
10

To either side kneel two high-court functionaries, dressed very like the Oba, but with plainer headdresses and fewer neck-rings.

They wear belts hung with small crocodile heads, the emblem of those authorized to conduct business with Europeans – and the heads and shoulders of two tiny Europeans can be seen floating in the background. The Europeans are Portuguese, who from the 1470s were sailing down the west coast of Africa in their galleons on their way to the Indies, but who were also seriously interested in West African pepper, ivory and gold. –A History of the World in 100 Objects, Neil MacGregor Which details from the passage help readers visualize the plaque? Check all that apply. “plainer headdresses and fewer neck-rings” “belts hung with small crocodile heads” “the heads and shoulders of two tiny Europeans” “sailing down the west coast of Africa” “West African pepper, ivory and gold”
Mathematics
2 answers:
Luden [163]3 years ago
7 0
"Plainer headdresses and fewer neck-rings”“Belts hung with small crocodile heads”“The heads and shoulders of two tiny Europeans”
scoray [572]3 years ago
5 0

Answer:

The first three. A, B, C

<em>You're welcome </em>

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Will give brainliest
SVETLANKA909090 [29]

Answer:

choice B) OM, NO, MN

Step-by-step explanation:

angle M = 180 - 40-77 = 63

The the larger the angle, the longer the opposite side .

5 0
3 years ago
5. A solid has a circle of radius r as its base. All sections of the solid perpendicular to the diameter along the x-axis are is
AleksandrR [38]

Answer:

 \frac{16r^3}{3}

Step-by-step explanation:

In this cross sections problem, we can integrate from -r to +r (so that the integral covers the entire base of the solid).

\int\limits^r_a {2(x^2+r^2 )} \, dx

The formatting for the integral did not let me put -r on the lower bound, so i replaced it with a, just know that a represents -r here.

Evaluating the integral gives use that it is equal to;

\frac{16r^3}{3}

Caution: this answer may not meet your needs, but this is the answer I have come up with with the given information.

If you found this answer helpful please consider leaving 5 stars, giving it a like, or if you asked this question, mark this answer as Brainliest. Thanks!

4 0
3 years ago
Police response time to an emergency call is the difference between the time the call is first received by the dispatcher and th
andrew11 [14]

Answer:

a) 0.7683 = 76.83% probability that a randomly selected emergency call is between 5 and 10 minutes.

b) 0.0606 = 6.06% probability that a randomly received emergency call is of less than 5 min.

c) 0.1711 = 17.11% probability that a randomly received emergency call is of more than 10 min.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 8.1 minutes and a standard deviation of 2.0 minutes.

This means that \mu = 8.1, \sigma = 2

a. between 5 and 10 min

This is the p-value of Z when X = 10 subtracted by the p-value of Z when X = 5.

X = 10

Z = \frac{X - \mu}{\sigma}

Z = \frac{10 - 8.1}{2}

Z = 0.95

Z = 0.95 has a p-value of 0.8289

X = 5

Z = \frac{X - \mu}{\sigma}

Z = \frac{5 - 8.1}{2}

Z = -1.55

Z = -1.55 has a p-value of  0.0606

0.8289 - 0.0606 = 0.7683

0.7683 = 76.83% probability that a randomly selected emergency call is between 5 and 10 minutes.

b. less than 5 min

p-value of Z when X = 5, which, found from item a, is of 0.0606

0.0606 = 6.06% probability that a randomly received emergency call is of less than 5 min.

c. more than 10 min

1 subtracted by the p-value of Z when X = 10, which, from item a, is of 0.8289

1 - 0.8289 = 0.1711

0.1711 = 17.11% probability that a randomly received emergency call is of more than 10 min.

7 0
3 years ago
Wish me luck<br><br>I have a math final next hour any pointers
amid [387]

Answer:

gooOoOood laCCccckK

5 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP!!!! WILL GIVE BRAINLIEST TO CORRECT OR FIRST ANSWER!!!!!
Airida [17]
Your answer is 67.5. Hope this helps!
6 0
4 years ago
Read 2 more answers
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