All categories

3 years ago

Choose two browsers and compare their security features.

Computers and Technology

1 answer:

777dan777 [17]3 years ago

4 0

Answer:

Brave & Mozilla Firefox

Explanation:

1. Brave

Brave browser is well known by its security, privacy, and speed. Just with a click you can turn security settings up high. Brave uses Chromium, Google’s open-source browser, which integrates strong sandboxing techniques. it also features automatic HTTPS upgrading and turns off plugins by default.

Brave primarily focus on privacy of it's users by auto blocking ads and tracking cookies that might stand as threat to the privacy of the users. Whereas most popular browsers allow you to install ad-blocker browser as an extensions. Another best part of Brave is that it also allows users to open private browsing tabs using Tor for maximum protection.

2. Mozilla

Mozilla browser is a an open-source, community-based development can achieve. Like many browsers, Firefox displays a padlock icon to let you know whether your connection is secure. However, Firefox’s padlock icon is surprisingly subtle. It’s easy to miss that your connection is unsecured.

This aside, Mozilla provides regular updates to Firefox, ensuring that any security flaws get patched quickly. If you’re seeking a private and secure browsing experience, combined with a quick and user-friendly interface, you should still consider Firefox.

You might be interested in

Lewis is using a stylus with his touch screen computer in order to draw a

Drupady [299]

Answer:

imput

Explanation:

4 0

2 years ago

Create a macro named mReadInt that reads a 16- or 32-bit signed integer from standard input and returns the value in an argument

timofeeve [1]

Answer:

;Macro mReadInt definition, which take two parameters

;one is the variable to save the number and other is the length

;of the number to read (2 for 16 bit and 4 for 32 bit) .

%macro mReadInt 2

mov eax,%2

cmp eax, "4"

je read2

cmp eax, "2"

je read1

read1:

mReadInt16 %1

cmp eax, "2"

je exitm

read2:

mReadInt32 %1

exitm:

xor eax, eax

%endmacro

;macro to read the 16 bit number, parameter is number variable

%macro mReadInt16 1

mov eax, 3

mov ebx, 2

mov ecx, %1

mov edx, 5

int 80h

%endmacro

;macro to read the 32 bit number, parameter is number variable

%macro mReadInt32 1

mov eax, 3

mov ebx, 2

mov ecx, %1

mov edx, 5

int 80h

%endmacro

;program to test the macro.

;data section, defining the user messages and lenths

section .data

userMsg db 'Please enter the 32 bit number: '

lenUserMsg equ $-userMsg

userMsg1 db 'Please enter the 16 bit number: '

lenUserMsg1 equ $-userMsg1

dispMsg db 'You have entered: '

lenDispMsg equ $-dispMsg

;.bss section to declare variables

section .bss

;num to read 32 bit number and num1 to rad 16-bit number

num resb 5

num1 resb 3

;.text section

section .text

;program start instruction

global _start

_start:

;Displaying the message to enter 32bit number

mov eax, 4

mov ebx, 1

mov ecx, userMsg

mov edx, lenUserMsg

int 80h

;calling the micro to read the number

mReadInt num, 4

;Printing the display message

mov eax, 4

mov ebx, 1

mov ecx, dispMsg

mov edx, lenDispMsg

int 80h

;Printing the 32-bit number

mov eax, 4

mov ebx, 1

mov ecx, num

mov edx, 4

int 80h

;displaying message to enter the 16 bit number

mov eax, 4

mov ebx, 1

mov ecx, userMsg1

mov edx, lenUserMsg1

int 80h

;macro call to read 16 bit number and to assign that number to num1

;mReadInt num1,2

;calling the display mesage function

mov eax, 4

mov ebx, 1

mov ecx, dispMsg

mov edx, lenDispMsg

int 80h

;Displaying the 16-bit number

mov eax, 4

mov ebx, 1

mov ecx, num1

mov edx, 2

int 80h

;exit from the loop

mov eax, 1

mov ebx, 0

int 80h

Explanation:

For an assembly code/language that has the conditions given in the question, the program that tests the macro, passing it operands of various sizes is given below;

;Macro mReadInt definition, which take two parameters

;one is the variable to save the number and other is the length

;of the number to read (2 for 16 bit and 4 for 32 bit) .

%macro mReadInt 2

mov eax,%2

cmp eax, "4"

je read2

cmp eax, "2"

je read1

read1:

mReadInt16 %1

cmp eax, "2"

je exitm

read2:

mReadInt32 %1

exitm:

xor eax, eax

%endmacro

;macro to read the 16 bit number, parameter is number variable

%macro mReadInt16 1

mov eax, 3

mov ebx, 2

mov ecx, %1

mov edx, 5

int 80h

%endmacro

;macro to read the 32 bit number, parameter is number variable

%macro mReadInt32 1

mov eax, 3

mov ebx, 2

mov ecx, %1

mov edx, 5

int 80h

%endmacro

;program to test the macro.

;data section, defining the user messages and lenths

section .data

userMsg db 'Please enter the 32 bit number: '

lenUserMsg equ $-userMsg

userMsg1 db 'Please enter the 16 bit number: '

lenUserMsg1 equ $-userMsg1

dispMsg db 'You have entered: '

lenDispMsg equ $-dispMsg

;.bss section to declare variables

section .bss

;num to read 32 bit number and num1 to rad 16-bit number

num resb 5

num1 resb 3

;.text section

section .text

;program start instruction

global _start

_start:

;Displaying the message to enter 32bit number

mov eax, 4

mov ebx, 1

mov ecx, userMsg

mov edx, lenUserMsg

int 80h

;calling the micro to read the number

mReadInt num, 4

;Printing the display message

mov eax, 4

mov ebx, 1

mov ecx, dispMsg

mov edx, lenDispMsg

int 80h

;Printing the 32-bit number

mov eax, 4

mov ebx, 1

mov ecx, num

mov edx, 4

int 80h

;displaying message to enter the 16 bit number

mov eax, 4

mov ebx, 1

mov ecx, userMsg1

mov edx, lenUserMsg1

int 80h

;macro call to read 16 bit number and to assign that number to num1

;mReadInt num1,2

;calling the display mesage function

mov eax, 4

mov ebx, 1

mov ecx, dispMsg

mov edx, lenDispMsg

int 80h

;Displaying the 16-bit number

mov eax, 4

mov ebx, 1

mov ecx, num1

mov edx, 2

int 80h

;exit from the loop

mov eax, 1

mov ebx, 0

int 80h

7 0

3 years ago

Please debug the below code in Java please.

lisabon 2012 [21]

Answer:

Check the explanation

Explanation:

//Bugs are highlighted in bold text

class Invoice

Declarations

private num invoiceNumber

private string customer

private num balanceDue

private num tax

public void setInvoiceNUMBER(num number)

Declarations

num LOW_NUM = 1000

num HIGH_NUM = 9999

if number > HIGH_NUM then

invoiceNumber = 0

else

if number < LOW_NUM then

invoiceNumber = 0

else

invoiceNumber = num

endif

return

public void setCustomer(string cust)

customer = cust

return

public void setBalanceDue(num balance)

//Bug balanceDue is Invoice class varible

//but it is assigned to balance .it gives error

balance = balanceDue

setTax()

return

private void setTax()

Declarations

//Bug TAX_RATE is declared as string

//but assigned a double value

string TAX_RATE = 0.07

tax = tax * TAX_RATE

return

public void displayInvoice()

output "Invoice #", invoiceNumber

output "Customer: ", customer

output "Due: ", balanceDue

output "Tax: ", taxDue

//Bug

//Invoice class has no variable called balance .it should be balanceDue

output "Total ", balance + taxDue

return

endClass

start

Declarations

Invoice inv1

Invoice inv2

Invoice inv3

//Warning

//it gives warning object taken but not initilaized

Invoice inv4

inv1.setInvoiceNumber(1244)

inv1.setCustomer("Brown")

inv1.setBalanceDue(1000.00)

inv1.displayInvoice()

inv2.setInvoiceNumber(77777)

inv2.setCustomer("Jenkins")

inv2.setBalanceDue(2000.00)

inv2.displayInvoice()

inv3.setInvoiceNumber(888)

inv3.setCustomer("Russell")

inv3.setBalanceDue(3000.00)

//Bug

//setTax method of Invioce doesnot take any arguments

inv3.setTax(210.00)

inv3.displayInvoice()

stop

//Here is the complete program in c++

//Run the program using Microsoft visual studio 2010 vc++

#include<iostream>

#include<iomanip>

#include<string>

using namespace std;

class Invoice

{

//class varibales

private:

int invoiceNumber;

string customer;

double balanceDue;

double tax;

//class methods

public:

void setCustomer(string cus);

void displayInvoice();

void setBalanceDue(double balance);

void setInvoiceNUMBER(int number);

void setTax();

};

void Invoice::displayInvoice()

{

cout<< setw(10)<<"Invoice #"<<setw(5)<<invoiceNumber<<endl;

cout<<setw(10)<<"Customer: "<<setw(5)<<customer<<endl;

cout<<setw(10)<<"Due: "<<setw(5)<<balanceDue<<endl;

cout<<setw(10)<<"Tax: "<<setw(5)<<tax<<endl;

//Bug

//Invoice class has no variable called balance .it should be balanceDue

cout<< "Total "<< balanceDue + tax<<endl;

}

void Invoice::setCustomer(string cust)

{

customer = cust;

}

void Invoice::setInvoiceNUMBER(int number)

{

const int LOW_NUM = 1000;

const int HIGH_NUM = 9999;

if( number > HIGH_NUM )

invoiceNumber = 0;

else

if (number < LOW_NUM )

invoiceNumber = 0;

else

invoiceNumber = number;

}

void Invoice::setBalanceDue(double balance)

{

balanceDue = balance;

}

void Invoice::setTax()

{

double TAX_RATE = 0.07;

tax = balanceDue * TAX_RATE;

}

int main()

{

Invoice inv1;

Invoice inv2;

Invoice inv3;

inv1.setInvoiceNUMBER(1244);

inv1.setCustomer("Brown");

inv1.setBalanceDue(1000.00);

inv1.setTax();

inv1.displayInvoice();

inv2.setInvoiceNUMBER(77777);

inv2.setCustomer("Jenkins");

inv2.setBalanceDue(2000.00);

inv2.setTax();

inv2.displayInvoice();

inv3.setInvoiceNUMBER(888);

inv3.setCustomer("Russell");

inv3.setBalanceDue(3000.00);

inv3.setTax();

inv3.displayInvoice();

system("pause");

return 0;

}

Kindly check the output image below.

5 0

3 years ago

3.1.14 Wormhole CodeHS <br><br> May I have it in a copy and paste, please?

Sauron [17]

Answer:

3.1.14 Wormhole CodeHS

Explanation:

3.1.14 Wormhole CodeHS

6 0

2 years ago

To what would you compare the transport layer?

Nikolay [14]

The above question has multiple choices as below

A. Data links
B. The post office
C. Driving a car
D. A train

The answer is (B) The Post Office.

In layman’s terms, transport layer is similar to the post office functions of delivering parcels and letters at the agreed delivery deadlines. It also notices any dropped info and re-transmits it.
Just like the post office, the transport layer directs messages and information between specific end users. If by mistake you write a letter to the wrong person, the letter will be returned and the postal employee will stamp it as address unknown.

6 0

3 years ago