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Gekata [30.6K]
3 years ago
11

Universal Containers has a requirement to integrate Salesforce with an external system to control record access. What option sho

uld the Architect consider when designing a solution?A. Use the Metadata API to maintain the related SObject recordsB. Use the Security API to modify the role hierarchy in SalesforceC. Use the SOAP API to maintain the related SObject_share recordsD. Use the SOAP API to create new Criteria-Based Sharing Rules in Salesforce
Computers and Technology
1 answer:
Inessa05 [86]3 years ago
8 0

Answer:

C. Use the SOAP API to maintain the related SObject_share records

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The _____ feature automatically corrects typing, spelling, capitalization, or grammar errors as you type them.
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Spell-check feature is the one that auto corrects any misspelled words
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3 years ago
What is the name of a variable that does not change values?
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Answer:

Constant variable

Explanation:

Constant variable is a data item whose value cannot change

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2 years ago
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Create an array of doubles to contain 5 values Prompt the user to enter 5 values that will be stored in the array. These values
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Solution :

$\#$include $$  

$\#$include $$    

void parse$\_$name($char \ full[]$, char first$[],$ char last$[])$

{

// to_get_this_function_working_immediately, _irst

// stub_it_out_as_below._When_you_have_everything_else

// working,_come_back_and_really_parse_full_name

// this always sets first name to "Noah"

int i, j = 0;

for(i = 0; full[i] != ' '; i++)

  first[j++] = full[i];

first[j] = '\0';  

// this always sets last name to "Zark"

j = 0;

strcpy(last, full+i+1);

// replace the above calls with the actual logic to separate

// full into two distinct pieces

}

int main()

{

char full[40], first[20], last[20];

double hours[5];

// ask the user to enter full name

printf("What is your name? ");

gets(full);

// parse the full name into first and last

parse_name(full, first, last);

// load the hours

for(int i = 0; i < 5; i++)

{

   printf("Enter hours for day %d: ", i+1);

   scanf("%lf", &hours[i]);

}

// create the time card

FILE* fp = fopen("timecard.txt", "w");

fprintf(fp, "First Name: %s\n", first);

fprintf(fp, "Last Name: %s\n", last);

double sum = 0.0;

for(int i = 0; i < 5; i++)

{

   fprintf(fp, "Day %i: %.1lf\n", i+1, hours[i]);

   sum += hours[i];

}

fprintf(fp, "Total: %.1f\n", sum);    

printf("Timecard is ready. See timecard.txt\n");

return 0;

}

3 0
3 years ago
Which of the following binary (base-2) numbers is LARGEST?
Lemur [1.5K]

Answer:

A. 11000000

Explanation:

A. 11000000 is 192

B. 01111111 is 127

C. 00000001 is 1

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