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djverab [1.8K]
3 years ago
7

The time needed for all college students to complete a certain paper-and-pencil maze follows a normal distribution with a popula

tion mean of 30 seconds and a population standard deviation of 3 seconds.
You wish to see if the mean time μ (where μ stands for population mean) is changed by vigorous exercise, so you have a group of nine college students exercise vigorously for 30 minutes and then complete the maze. It takes them an sample average of 31.2 seconds to complete the maze. Use this information to test the hypotheses:
H0: μ = 30,
Ha: ≠30
at the significance level of 0.01.
You conclude:

a) There is not enough evidence to support the claim.
b) There is enough evidence to support the claim.
Mathematics
1 answer:
blsea [12.9K]3 years ago
5 0
Are you gay just asking huh
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Step-by-step explanation:

No, Lance's thinking is wrong because you cannot compare decimal numbers with alphabetizing words. For example, if we compare 37.6 to 7.42 using the method of Lance, we would probably say 37.6 is less than 7.42 because 3 is less than 7. But it is wrong. The 3 in 37.6 is in the tens place. On the other hand, 7.42 contains no tense. Therefore, 37.6 is actually higher.

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