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eduard
3 years ago
5

CAN SOMEONE PLEASE HELP ME WITH THIS QUESTION?

Mathematics
1 answer:
Dimas [21]3 years ago
4 0

Answer:

  B.  More than one quadrilateral exists with the given conditions, and all instances must be isosceles trapezoids.

Step-by-step explanation:

In a parallelogram, adjacent angles are supplementary. They are only congruent if the parallelogram is a rectangle. In this problem, adjacent angles are both congruent and acute. If this were a triangle, it would guarantee the triangle is isosceles.

The fact that opposite angles are supplementary guarantees that the fourth side of the figure is parallel to the base between the acute angles. That makes the figure an isosceles trapezoid. Unless specific angles and side lengths are specified, the description matches <em>any</em> isosceles trapezoid.

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Debra borrowed $8000 at a rate of 18% compounded semiannually. Assuming she makes no payment, how much will she owe after 9 year
Marina CMI [18]

Answer:

She owe $37736.96 after 9 years .

Step-by-step explanation:

Debra borrowed $8000 at a rate of 18% compounded semiannually

We are supposed to find how much will she owe after 9 years

Principal = 8000

Rate of interest = 18% =0.18

No. of compounds per year = 2

Time = 9 years

Formula : A= P(1+\frac{r}{n})^{nt}

Substitute the values in the formula :

A= 8000(1+\frac{0.18}{2})^{2 \times 9}

A= 37736.96

Hence She owe $37736.96 after 9 years .

5 0
3 years ago
Math:
Dahasolnce [82]

Answer:

a) x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}, x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}, b) x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}, x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

Step-by-step explanation:

a) The equation must be rearranged into a form with one fundamental trigonometric function first:

\sqrt{3}\cdot \csc x - 2 = 0

\sqrt{3} \cdot \left(\frac{1}{\sin x} \right) - 2 = 0

\sqrt{3} - 2\cdot \sin x = 0

\sin x = \frac{\sqrt{3}}{2}

x = \sin^{-1} \frac{\sqrt{3}}{2}

Value of x is contained in the following sets of solutions:

x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}

x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

b) The equation must be simplified first:

\cos x + 1 = - \cos x

2\cdot \cos x = -1

\cos x = -\frac{1}{2}

x = \cos^{-1} \left(-\frac{1}{2} \right)

Value of x is contained in the following sets of solutions:

x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}

x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

7 0
3 years ago
Use the distance formula to find the distance if point a is 3,4 and point b is 1,2
Fed [463]

Answer:

square root of 8

Step-by-step explanation:

3 0
3 years ago
4. The students in Mr. Michael’s art class are decorating a booth for Harvest Day. They have blue cloth that is 60 inches long,
MrRissso [65]

Length of blue cloth is 60 inches , length of gold cloth is 48 inches and length of white cloth is 72 inches.

<u>a.</u>  

As, the length of all pieces are equal, so for getting the greatest possible length of the pieces, we need to find <u>GCF(greatest common factor) of 60, 48 and 72. </u>

First we will factor out all three numbers completely......

60=2*2*3*5\\ \\ 48=2*2*2*2*3\\ \\ 72=2*2*2*3*3

The common factors are: 2, 2 and 3

Thus the GCF = 2*2*3=12

So, the greatest possible length of the pieces without having any cloth left over will be 12 inches.

<u>b. </u>  

For finding the number of pieces for each color cloth, we will just <u>divide the length of each cloth by 12</u>. So...

Number of pieces for blue cloth =\frac{60}{12}=5

Number of pieces for gold cloth =\frac{48}{12}=4 and

Number of pieces for white cloth =\frac{72}{12}=6

4 0
3 years ago
What is the measure of OAC
Lady bird [3.3K]

Answer:

27°

Step-by-step explanation:

  • A tangent meets a radius at 90°
  • Angles in a trainable sum to 180°
  • 180 - 90 - 63 = 27°
4 0
2 years ago
Read 2 more answers
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