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eduard
3 years ago
5

CAN SOMEONE PLEASE HELP ME WITH THIS QUESTION?

Mathematics
1 answer:
Dimas [21]3 years ago
4 0

Answer:

  B.  More than one quadrilateral exists with the given conditions, and all instances must be isosceles trapezoids.

Step-by-step explanation:

In a parallelogram, adjacent angles are supplementary. They are only congruent if the parallelogram is a rectangle. In this problem, adjacent angles are both congruent and acute. If this were a triangle, it would guarantee the triangle is isosceles.

The fact that opposite angles are supplementary guarantees that the fourth side of the figure is parallel to the base between the acute angles. That makes the figure an isosceles trapezoid. Unless specific angles and side lengths are specified, the description matches <em>any</em> isosceles trapezoid.

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Step-by-step explanation:

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An artificial lake is in the shape of a rectangle and has an area of 9/20 square mile the width of the lake is 1/5 the length of
DIA [1.3K]
Answer:  The dimensions are:   " 1.5 mi.  ×  ³⁄₁₀  mi. " .
_______________________________________________
             { length = 1.5 mi. ;  width =  ³⁄₁₀  mi. } .
________________________________________________
Explanation:
___________________________________________
Area of a rectangle:

A = L * w ; 

in which:  A = Area = (9/20) mi.² ,
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                w = width = (1/5)*L = (L/5) = ?
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  A = L * w ;  we want to find the dimensions; that is, the values for
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Plug in our given values:
_______________________________________
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     → (9/20) = (L/1) * (L/5) = (L*L)/(1*5) = L² / 5 ;
   
          ↔  L² / 5  = 9/20 ;
 
            →  (L² * ? / 5 * ?) = 9/20 ?    

                →     20÷5 = 4 ;  so; L² *4 = 9 ;
 
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                   →  Divide EACH side of the equation by "4" ;
           
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______________________________________
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___________________________________________          
 
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Let us check our answers:
_______________________________________
(3/2 mi.) * (3/10 mi.) =? (9/20) mi.² ??

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______________________________________________________
So the dimensions are: 

Length = (3/2) mi. ;  write as: 1.5 mi.

width = ³⁄₁₀ mi.
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or; write as:  " 1.5 mi.  ×  ³⁄₁₀ mi. " .
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