Area of pool edge = Area of big rectangle - Area of the pool
Area of pool edge = Area of the pool = 40 × 60 = 2400 ft²
2400 = Area of big rectangle - 2400
Area of big rectangle = 2400 + 2400
Area of big rectangle = 4800
Length × width = 4800
From the diagram, we need the length to be [x + x] more than the length of the pool, where x is the distance from the pool edge to the patio edge.
We also need the width of the big rectangle to be [[x + x] more than the width of the pool.
Length = 60 + 2x
Width = 40 + 2x
Length × Width = [60+2x] × [40+2x]
4800 = 2400 + 120x + 80x + 4x²
0 = 4x² + 200x - 2400
0 = 4[x² + 50x - 600]
0 = x² + 50x - 600
0 = [x - 60] [x + 10]
x - 60 = 0 OR x + 10 = 0
x = 60 OR x = -10
We can only use the positive value of x since the context is length
Hence, x = 60
Answer:
Step-by-step explanation:
1/8 = 1/9 + x ...multiply by LCD of 72
9 = 8 + 72x
9 - 8 = 72x
1 = 72x
1/72 = x
1/8 = 1/10 + x....multiply by 40
5 = 4 + 40x
5 - 4 = 40x
1 = 40x
1/40 = x
1/8 = 1/11 + x....multiply by 88
11 = 8 + 88x
11 - 8 = 88x
3 = 88x
3/88 = x
can all unit fractions be made in more then 1 way like this ?
not to sure because that last one....because it has been that a unit fraction is the outcome of adding together 2 unit fractions...but that last one...3/88 is not a unit fraction
Answer:
A
Step-by-step explanation:
Answer:
yes
Step-by-step explanation:
-8x-2y<6
put in x and y and see if it is less than 6
-8(3) -2(2) <6
-24 -4 <6
-28 <6
yes
it is a solution