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3 years ago

If BI=9 and HA=15, find the scale factor

Mathematics

1 answer:

inessss [21]3 years ago

7 0

Answer:

5:3

Step-by-step explanation:

to find the scale factor you set up the proportion as 15/9 and reduce to 5/3

You might be interested in

Solve the following inequality. 2P - 3 > P + 6

WITCHER [35]

Answer:

P > 9

Step-by-step explanation:

first, you add 3 to both sides,

2p > P + 9

then subtracts P from both sides,

P > 9

your final answer is P > 9

Hope this helps! :)

7 0

2 years ago

Read 2 more answers

3/5 of your teammates want to wear red jerseys. 1/4 of those teammates also want to wear red pants. What fraction want to wear r

Lina20 [59]

Answer:

3/20

Step-by-step explanation:

1/4 of 3/5= 3/20

hope its clear

8 0

4 years ago

You deposit $3000 in a savings account that earns 2.9% annual interest compounded monthly. You also save $80 per month in a safe

Jlenok [28]

Answer:

C(t)=3000(1.002417)^12t+960t

if T=1 year then the saving will be : 4048.17

Step-by-step explanation:

3000 deposit amount, 2.9 compound monthly interest . save 80 dollars per month at home .

A=p(1+r)^t

A=3000(1+0.029/12)^12t

A=3000(1.002417)^12t dollars

for the amount saved at home=80*12t=960t dollars

C(t)=3000(1.002417)^12t+960t

if T=1 year then the saving will be :

C(t)=3000(1.002417)^12t+960t

=3088.17+960= 4048.17 dollars

7 0

3 years ago

Question 1,2, and 3 how do i factor those? Can you show the work and explain how?

DiKsa [7]

1: $3n^{2}+9n+6$

notice that each part is divisible by 3

$3n^{2}$ ÷ 3 = $n^{2}$

9n ÷ 3 = 3n

6 ÷ 3 = 2

so it becomes $3(n^{2} +3n+2)$

3n can be rewritten as 2n+n

-you want to rewrite it into two numbers that multiply to the number that's alone (in this case 2)

which would get you

$3(n^{2} +2n+n+2)$

Now that it's rewritten, you can factor out n + 2 from the equation.

the answer is

3(n+2)(n+1)

And you can check that by multiplying (n+2)(n+1) which is $n^{2} +2n+n+2$ and then each of those by 3, which is $3n^{2} +6n+3n+6$ or $3n^{2}+9n+6$ , our origional equation

2: $28+x^{2} -11x$

So I rewrote this as $x^{2} -11x+28$ (it's the same thing, just reordered using the commutative property)

now -11x can be rewritten as -4x-7x

(remember, the two numbers should multiply to equal 28, which is our constant.)

$x^{2} -4x-7x+28$

now we can factor out x from the first expression and -7 from the second

$x(x-4)-7(x-4)$

and lastly you factor out x-4,

which would give you

(x-4)(x-7)

Make sure to check your work and make sure it multiplies to $x^{2} -11x+28$

3: $9x^{2} -12x+4$

The first thing I notice when looking at this problem is that both 9 and 4 are perfect squares. Not only that, but they are the squares of 2 and 3, which are products of -12

So if you rewrite 9 as $3^{2}$ and 4 as $2^{2}$ , the equation becomes