2a + 3b = 6 --> Equation 1
5a + 2b = 4 --> Equation 2
Equation 1 * 5 --> 10a + 15b = 30
Equation 2 * 2 --> 10a + 4b = 8
Equation 1 - Equation 2 --> 11b = 22 --> b = 2
Sub b=2 in Equation 1 (or 2, either works):
2a + 3b = 6
2a + 3(2) = 6
2a + 6 = 6
2a = 0
a = 0
b = 2, a = 0
Answer:
729
Step-by-step explanation:
Its a bit long to describe here but the following link will show you how:-
www.mathopenref.com/printdividesegment.html
H = 10 cm, a - edge;
V = 1/3 a²√3 / 4 * h
h² = ( 2/3 * a√3 / 2 )² + a²
100 = a²/3 + a²
100 = 4 a² / 3
a² = 75
a = √75
a = 5 √3 cm
V = 1/2 * 75√3 / 4 * 10 = 250√3 / 4 = 62.5√3 cm³ ≈ 108.25 cm³
Answer:

From this info and using the empirical rule we know that we will have about 68% of the scores between:


95 % of the scores between:


And 99.7% of the values between


Step-by-step explanation:
For this problem we can define the random variable of interest as "the student grades" and we know that the distribution for X is given by:

From this info and using the empirical rule we know that we will have about 68% of the scores between:


95 % of the scores between:


And 99.7% of the values between

