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cupoosta [38]
2 years ago
11

A boat has a speed of 15 mph in still water. It travels downstream from Greentown to Glenavon in g hours. It then goes back upst

ream from Glenavon to Cambria, which is 2 miles downstream from Greentown, in g hours. Find the rate of the current.
I would really appreciate any help provided for this problem, please show your steps, and I'll mark you brainliest :)

Mathematics
1 answer:
valentina_108 [34]2 years ago
7 0

Answer:

The distance from Greentown to Glenavon is D1 = g*(15+x) miles downstream.

The distance from Glenavon to Cambria is D2 = g*(15-x) miles upstream.

The difference D1 - D2 is 2 miles, according to the condition.

It gives you an equation g*(15+x) - g*(15-x) = 2, which you can easily solve and find "x", the rate of the current. x = 1/g miles per hour.

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Erica makes necklaces from beads. Each necklace consists of blue, white and green beads in the ratio of 6 : 4: 1 One necklace ne
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<u>For one Necklace you would need...</u>

24 blue beads.

16 white beads.

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Ratio: 24: 16: 4

Step-by-step explanation:

If you quadruple the amount of beads from the original amount (6 : 4: 1), the total beads for that necklace will be 44.

Step 1: 6 x 4 = 24 (amount of blue beads in necklace).

Step 2: 4 x 4 = 16 (amount of white beads in necklace).

Step 3: 1 x 4 = 4 (amount of green beads in necklace).

Now check to see if the total of all types of beads sum up to 44:

Step 4: 24 + 16 + 4 = 44

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There is your answer:

You need 24 blue beads, 16 white beads, and 4 green beads to have a total sum of 44 beads in that one necklace.

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2 years ago
What are the zeros of the function f(x) =x^2-11x+24 ?
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Step-by-step explanation:

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Si una empresa obtiene un préstamo de S/3000 a seis años de plazo, con una tasa de interés compuesto del 15 % anual capitalizabl
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Answer:

VF= $3.281,42

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Step-by-step explanation:

Dada la siguiente información:

Prestamo (P)= $3.000

Tasa (i)= 0,015/2= 0,0075

Cantidad de periodos (n)= 6*2= 12 semestres

<u>Para calcular el valor final del prestamos, tenemos que usar la siguiente formula:</u>

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