I REALLY NEED HELPM ASAP SOON!!!!

B<br><img src="https://tex.z-dn.net/?f=%203%C3%B75%20%2B2%C3%B7b%3D1%20" id="TexFormula1" title=" 3÷5 +2÷b=1 " alt

Grace [21]

Answer: b=5

Step-by-step explanation:

Multiply all terms by b and cancel:

3b/5+2=1b

3/5b+2=b(Simplify both sides of the equation)

3/5b+2−b=b−b(Subtract b from both sides)

−2/5b+2=0

−2/5b+2−2=0−2(Subtract 2 from both sides)

−2/5b=−2

(5−2)*(−25b)=(5−2)*(−2)(Multiply both sides by 5/(-2))

b=5

Check answers. (Plug them in to make sure they work.)

b=5 (Works in the original equation)

Answer:

b=5

Hope this helps! ;)

5 0

3 years ago

A ball is thrown vertically so that its height above the ground after t

Alina [70]

Answer is below.......

4 0

3 years ago

Acceptance Sampling Random sampling from a large lot of manufactured items yields a number of defective items X with an approxim

AfilCa [17]

Answer:

Step-by-step explanation

Let β = np, n= 5 and p= 0, 0.1, 0.3, 0.5, 0.9 and 1

x > a, a= 0

The probability of an item inspected, P(x) = β∧x*e∧-β/x!

a) For x= 1: β = 5 X 0 = 0

P(x=1) = 0

For x = 2: β = 5 X 0.1 = 0.5

P(x=2) = 0.5²*e∧-0.5/2!

For x = 3: β = 5 X 0.3 = 1.5

P(x=3) = 1.5³*e∧-1.5/3!

For x =4: β = 5 X 0.5 = 2.5

P(x=4) = 2.5∧4*e∧-2.5/4!

For x = 5: β = 5 X 0.9 = 4.5

P(x=5) = 4.5∧5*e∧-4.5/5!

For x= 6: β = 5 X 1 = 5

P(x= 6) = 5∧6*e∧-5/6!

b) For plan1, x = 1: β + 10 X 0.1 = 1

P(x=1) = e∧-1/1! = 1/e = 1/2.718 = 0.368

For plan2, x=20: β = 100 X 0.1 = 10

P(x=20) = 10∧20*e∧-10/20!

Plan 2 is preferable because the probability of success is very small and the number of trial is comparatively large, hence, the poisson distribution will be suitable probability model.

d) Plan 1 is prefered instead, because the probability of success is larger and more profit is made.

e) Plen 2 is prefered, because it will be cheaper to afford.

8 0

3 years ago

Write an equation of the line that is perpendicular to the line y = 1 2 x + 8 that passes through the point (4,6)

Katen [24]

Answer:

$\large\boxed{y=-2x+14}$

Step-by-step explanation:

$\text{Let}\ k:y=_1x+b_1\ \text{and}\ l:y=m_2x+b_2.\\\\l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\============================\\\\\text{We have}\ y=\dfrac{1}{2}x+8\to m_1=\dfrac{1}{2}.\\\\\text{Therefore}\ m_2=-\dfrac{1}{\frac{1}{2}}=-2.\\\\\text{The equation of the searched line:}\ y=-2x+b.\\\\\text{The line passes through }(4,\ 6).$