Hey Child.
The answer to this is 1 or 7:
To find the range for the number of measures played to satisfy our solution, we must solve for x using s = 80.
Next, we subtract 50 from both sides of the equation.
Next, we divide both sides of the equation by 10
Next, to eliminate the absolute value bars, we will add a ± sign in front of our s value, 3.
Finally, we add 4 to both sides of our equation giving us 4 ± 3 = x
Separating this into two equations, we get 4 - 3 = x and 4 + 3 = x
Therefore, x, the number of measures of music played, must be either 1 or 7.
Hope It Helped!~
<h3>¬❤♪❤♪¬</h3>
I think 7a^3b^6, but im not sure so im sorry if it is wrong
Answer:
₹2520
Step-by-step explanation:
First, converting R percent to r a decimal
r = R/100 = 10%/100 = 0.1 per year,
then, solving our equation
I = 12600 × 0.1 × 2 = 2520
I = ₹ 2,520.00
The simple interest accumulated
on a principal of ₹ 12,600.00
at a rate of 10% per year
for 2 years is ₹ 2,520.00.
Qn. 1
Lower bound for Zoe's weight = 62 - (1/2) = 62 - 0.5 = 61.5 kg
Qn. 2
Upper bound for length AB = 8.3+ (0.1/2) = 8.3+0.05 = 8.35 cm
Qn. 3
Upper bound for Anu's wight = 83+(0.5/2) = 83+0.25 = 83.25 kg
Qn. 4
Lower bound for length CD = 27-(0.5/2) = 27-0.25 = 26.75 cm
Qn. 5
Upper bound for sides of the hexagon = 3.6+(0.1/2) = 3.6+0.05 = 3.65 cm
Upper bound for the perimeter = upper bound for the sides*6 = 3.65*6 = 21.9 cm
Qn. 6
Perimeter = 4*length => side = Perimeter/4 = 24/4 = 6
Bound = 0.5/4 = 0.125
Lower bound of the length = 6-0.125 = 5.875 cm
Qn. 7
For the area,
Upper bound = 80+(10/2) 80+5 = 85 cm^2
For the length
Upper bound = 12+(1/2) = 12+0.5 = 12.5
Then, upper bound for the width = Upper bound for the area/upper bound for the length = 85/12.5 = 6.8 cm
Qn. 8
Lower bound for the area = 230-(1/2) = 230-0.5 = 229.5 cm^2
Lower bound for the sides of the square = Sqrt(Lower bound of the area) = Sqrt (229.5) = 15.15
Then,
Lower bound of perimeter = 4(Length) = 4*15.15 = 60.6 cm
