So, to find the solution to this problem, we will we using pretty much the same method we used in your previous question. First, let's find the area of the rectangle. The area of a rectangle is length x width. The length in this problem is 16 and the width is 3, and after multiplying these together, we have found 48 in^2 to be the area of the square. Next, we can find the area of the trapezoid. The area of a trapezoid is ((a+b)/2)h where a is the first base, b is the second base, and h is the height. In this problem, a=16, b=5, and h=10. So, all we have to do is plug these values into the area formula. ((16+5)/2)10 = (21/2)10 = 105. So, the area of the trapezoid is 105 in^2. Now after adding the two areas together (48in^2 and 105in^2), we have found the solution to be 153in^2. I hope this helped! :)
ABC = XYZ by SAS
AB = XY - Side
A = X - Angle
So you want to find another congruent <em>side</em>.
Removing the taken possible side, two sides can be congruent.
Either :
BC = YZ
<em>OR</em>
AC = XZ
Answer:
I think it is 11 Feet
Step-by-step explanation:
Answer:
A= 5
B= 3
Step-by-step explanation:
A= 5 +5+5+5= 20
B= 3 (length) x 3 (width)
Answer:
The correct option is;
Yes, the line should be perpendicular to one of the rectangular faces
Step-by-step explanation:
The given information are;
A triangular prism lying on a rectangular base and a line drawn along the slant height
A perpendicular bisector should therefore be perpendicular with reference to the base of the triangular prism such that the cross section will be congruent to the triangular faces
Therefore Marco is correct and the correct option is yes, the line should be perpendicular to one of the rectangular faces (the face the prism is lying on).
