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Anarel [89]
2 years ago
11

9 pipes can fill a tank in 4 hours. How long will it take if there are 12 pipes of same

Mathematics
1 answer:
Rufina [12.5K]2 years ago
7 0

Answer:

3 hours

Step-by-step explanation:

9 pipes/4 hours= 3 pipes/1 hour

The rate the pipes fill a tank will change by 1 hour as there are 3 more pipes.

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On a scale drawing of a steel I- beam, the height of a beam is 2 1/2
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Answer:On a scale drawing of a steel I-beam , the height of the beam is 2 1/2 in. The scale is 1/4 in = 6 feet. What is the actual height of the I-beam. \(12\)

Step-by-step explanation:

5 0
2 years ago
A 78 gram sample of Uranium loses half of its mass each year. What is the exponential equation? Please explain why A is the corr
Fiesta28 [93]

Answer:

A

Step-by-step explanation:

The first answer is correct because we have a decay factor.

The sample is losing mass, so the number that is being multiplied by a power of x must be less than 1.

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8 0
2 years ago
Kyle is making a frame for a rectangular piece of art. The length of the frame is 3 times the width, as shown below.
NeX [460]

Answer:

3.75 feet

Step-by-step explanation:

The length of the frame is 3 times the width.

Let the width be x.

The length will be 3x.

Kyle uses 10 feet of wood to make the frame. This means that the perimeter is 10 feet.

The perimeter of a rectangle is:

P = 2(L + W)

=> 10 = 2(3x + x)

=> 10/2 = 4x

5 = 4x

=> x = 5/4 = 1.25 feet

The width is 1.25 feet. The length is therefore:

1.25 * 3 = 3.75 feet

5 0
3 years ago
Consider the equation below -2(5x + 8) = 14 + 6x complete the statements below with the process used to achieve steps 1-4
Ad libitum [116K]

Step-by-step explanation:

1. Distribute the -2. multiply-2 with 5x and 8. it will be -10x-16=14+6x. For me, i make small numbers negative or positive than big ones. Add 16 to both sides. it will be -10x=30+6x. Subtract 6x. -10x-6x=-16x. Divide both sides by 16. x=30/16= 1 and 14/16

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3 years ago
The graph of the function y=f(x)
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The range is the high and low points. 

So (5, 2] 
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3 years ago
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