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Liula [17]
3 years ago
7

In a given course a student receives preliminary examination grades of 81, 85, and 95. The final examination is weighed for one-

third and the average of the preliminary grades is weighed as 2/3 of the final grade. What should the final examination grade be for a semester average of 90?
99
96
93
88
87
Mathematics
1 answer:
Vsevolod [243]3 years ago
4 0

Answer:

B. 96

Step-by-step explanation:

Let x represent score of final third exam.

We have been given that in a given course a student receives preliminary examination grades of 81, 85, and 95.

Let us find average of preliminary scores.

\frac{81+85+95}{3}=\frac{261}{3}=87

We have been given that the final examination is weighed for one-third and the average of the preliminary grades is weighed as 2/3 of the final grade. This means that final grade is equally weighed into 3 parts. The two parts are 87 each and third part is x.

Using our given information, we can set an equation as:

\frac{87+87+x}{3}=90

\frac{174+x}{3}=90

\frac{174+x}{3}*3=90*3

174+x=270

174-174+x=270-174

x=96

Therefore, the final examination grade should be 96 for a semester average of 90.

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Answer:

Option B is correct = 0.3 \times 81

Step-by-step explanation:

<u>The complete question is:</u> Which of the following options have the same value as 30% of 81?

Group of choices is:

(A) \frac{30}{100}\times 81 \times 100

(B) 0.3 \times 81

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Now, the expression given to us is 30% of 81.

Simplifying the above expression we get;

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Now, we will solve each of the given options and then see which option matches with our calculation.

Option (A) is given;

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This doesn't match with our answer, so this option is not correct.

Option (B) is given;

0.3 \times 81  

<u><em>This matches with our answer, so this option is correct.</em></u>

Option (C) is given;

0.03 \times 81  

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Option (D) is given;

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This doesn't match with our answer, so this option is not correct.

Option (E) is given;

30 \times 81  

This doesn't match with our answer, so this option is not correct.

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