
1) A figure formed by line segments only is called a <u>polygon</u><u> </u> .
2) Perimeter of a regular polygon is <u>Number </u><u>of </u><u>sides </u><u>×</u><u> </u><u>Measure </u><u>of </u><u>each </u><u>side </u><u>.</u>
3) Perimeter of a irregular polygon is <u>sum </u><u>of </u><u>all </u><u>sides </u><u>.</u>
4) Two circles with same centre but different radii is called <u>Concentric </u><u>circles</u><u>.</u>
5) Ratio of circumference of circle to its diameter is <u>pie </u> and is named by Greek letter <u>π </u>.
6) Distance around the circle is called<u> </u><u>circumference</u><u>.</u>
7) A chord of the circle contains exactly <u>two points</u> on a circle.
8) 1 hectare = <u>1</u><u>0</u><u>,</u><u>0</u><u>0</u><u>0</u><u> </u><u>m²</u>
<h3>
<u>I </u><u>hope</u><u> </u><u>it </u><u>helped </u><u>ツ</u></h3>
Part (1):
The sum of the internal angles in any triangle is 180.
This means that:
∠1 + ∠2 + ∠3 = 180
We are given that:
∠1 + ∠3 = 154°
Therefore:
∠2 + 154 = 180
∠2 = 180 - 154 = 26°
Part (2):
Complementary angles are defined as angles that sum up to 90°
Supplementary angles are defined as angles that sum up to 180°
We know that ∠1 and ∠3 sum up to 154°.
This means that they are neither complementary nor supplementary.
Hope this helps :)
Just use algebra to rearrange the terms so for s=1/2at^2 and solving for a we get 2s=at^2 so 2s/t^2=a
solving s=1/2at^2 for t gives 2s=at^2 which leads to 2s/a=t^2 so t=sqrt(2s/a)
filling in the numbers for 3 since a = 2s/t^2 we get a= (2(20.5m))/5s^2 =1.64m/s^2 the correct units in the answer indicate a possible correct answer since the units of acceleration are m/s^2.
4. using the value for a from question 3 and using 42.5 meters for s and solving for t we get sqrt((2s)/a) = sqrt((2*42.5m)/1.64m/s^2)= approximately 7.2s you can see the m's cancel and you are left s^2 as the units and the sqrt(s^2) = s so again the correct units indicate that 7.2s is probably correct. (These answers ARE correct though). checking the units gives a kinda quick assurance you are on the right path.