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otez555 [7]
2 years ago
12

Change each fraction to higher terms 1/5=?/10

Mathematics
1 answer:
erma4kov [3.2K]2 years ago
4 0

Answer:

2/10

Step-by-step explanation:

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Could someone help me
Strike441 [17]
1. The area of the rectangle is 336. 14 times 24= 336 or width times length= 336.
2. The perimeter of the rectangle is 76. Because, 2 times(14+24)=76
3. If x= 10, the area would still be 336
5 0
2 years ago
I need the answer quick please!!!!
4vir4ik [10]

Answer: it says $18 plus $3. The equation would be y = 3x + 18 like said. And for the other one it’s y = 5x + 12 following the same logic.

I know I’m not helping much but I’m rushing rn. Hope this helps?

4 0
3 years ago
What’s the answer for 21?
Keith_Richards [23]

Answer:

C

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A: 2 in. by 2 in. by 1 in. = 4 cubic inches

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4 0
2 years ago
Read 2 more answers
Find m<br> A. 38<br> B. 76<br> C. 142<br> D. 71
baherus [9]
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8 0
3 years ago
Read 2 more answers
Given a triangle with vertices P(-9,7), Q(-3,7), and R(-3,1), and S is the midpoint of PQ and T is the midpoint of QR, what is t
Natalija [7]
Check the picture below.

so we know S is the midpoint of PQ, and T is the midpoint of QR, thus

\bf ~~~~~~~~~~~~\textit{middle point of 2 points }\\\\&#10;\begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&P&(~ -9 &,& 7~) &#10;%  (c,d)&#10;&Q&(~ -3 &,& 7~)&#10;\end{array}\quad&#10;%   coordinates of midpoint &#10;\left(\cfrac{ x_2 +  x_1}{2}\quad ,\quad \cfrac{ y_2 +  y_1}{2} \right)&#10;\\\\\\&#10;S=\left( \cfrac{-3-9}{2}~,~\cfrac{7+7}{2} \right)\implies S=(-6,7)\\\\&#10;-------------------------------

\bf ~~~~~~~~~~~~\textit{middle point of 2 points }\\\\&#10;\begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&Q&(~ -3 &,& 7~) &#10;%  (c,d)&#10;&R&(~ -3 &,& 1~)&#10;\end{array}&#10;\\\\\\&#10;T=\left(\cfrac{-3-3}{2}~,~\cfrac{1+7}{2}  \right)\implies T=(-3,4)

so, what's the distance from S to T?

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\&#10;\begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&S&(~ -6 &,& 7~) &#10;%  (c,d)&#10;&T&(~ -3 &,& 4~)&#10;\end{array}\\\\\\ &#10;%  distance value&#10;d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}&#10;\\\\\\&#10;ST=\sqrt{[-3-(-6)]^2+[4-7]^2}\implies ST=\sqrt{(-3+6)^2+(4-7)^2}&#10;\\\\\\&#10;ST=\sqrt{3^2+(-3)^2}\implies ST=\sqrt{18}\implies ST=\sqrt{9\cdot 2}&#10;\\\\\\&#10;ST=\sqrt{3^2\cdot 2}\implies ST=3\sqrt{2}

5 0
3 years ago
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