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ipn [44]
3 years ago
11

Solve the following system of equations graphically on the set of axes below.

Mathematics
1 answer:
Elza [17]3 years ago
3 0
The 1st line slopes up with y intercept = 5
the 2nd line slopes down with y intercept =-5

they intersect in quadrant II at (-6,4)

Here’s an example to go along with your problem, plug in your numbers!
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a bricklayer needs to order 6300kg of building sand.one grain of this sand weighs 7x10^-5. how many grains of sand are there in
gavmur [86]

Answer:

44.1 x 10^-2

Step-by-step explanation:

Since one grain

= 7 x 10^-5

6300kg = 7 x 10^-5 x 6300

Put 6300 in standard form

7 x 10^-5 x 6.3 x 10^3

Multiply the whole numbers and add the exponents

7 x 6.3 x 10^-5 + 3

44.1 x 10^-2

There are 44.1 x 10^-2 grains of sand in 6300kg

5 0
3 years ago
Use DeMoivre's Theorem to find (3cis*pi/6)^3
Sonbull [250]

The correct value of (3cis(pi/6))³ is 27i.

<h3>What is Complex Number?</h3>

Complex numbers are numbers that consist of two parts — a real number and an imaginary number. Complex numbers are the building blocks of more intricate math, such as algebra.

Given the complex number in polar coordinate expressed as

z = r(cos∅+isin∅)

zⁿ =  {r(cos∅+isin∅)}ⁿ

According to DeMoivre’s Theorem;

zⁿ =  rⁿ(cosn∅+isinn∅)

Given the complex number;

(3cis(pi/6))³

= {3(cosπ/6 + isinπ/6)}³

Using  DeMoivre’s Theorem;

= 3³(cos3π/6 + isin3π/6)

=  3³(cosπ/2 + isinπ/2)

= 3³(0 + i(1))

= 27i

Thus, the correct value of (3cis(pi/6))³ is 27i.

Learn more about Complex number from:

brainly.com/question/10251853

#SPJ1

7 0
2 years ago
Natalie is cutting construction paper into rectangles for a project. She needs to cut one rectangle that is 6 inches x 13 1/2 in
Leya [2.2K]

Answer:

1. 81

2. 108 1/2

3. 189 1/2

Step-by-step explanation:

7 0
3 years ago
NEED HELP RIGHT NOW PLEASE HELP!!!!!!
Gekata [30.6K]
The rule is to subtract 6
3 0
4 years ago
Read 2 more answers
Explain Steps. Do not answer. <br>#10 and 11<br>Questions are in the Picture
svet-max [94.6K]

Answer:

Step-by-step explanation:

For problem 10:

1. AE/ED=AC/CB (Since triangle ABC is similar to triangle ADE, we can determine that the ratio of AE to ED is equal to the ratio of AC to CB)

2. AE/ED=(AE+EC)/CB (Rewrite AC as the sum of the lengths forming it; This is sometimes referred to as the Partition Postulate)

3. 9/x=(9+6)/10 (Substitute the given values into this equation)

4. x=6 (Use algebra to solve for x)

For problem 11:

1. AG/AB=AE/AD (Use the same strategy as step one in problem 10, since the rectangles are similar we can create this equation)

2. AG/(AG+GB)=AE/(AE+ED) (Rewrite sides as the some of their parts)

3. 14/(14+7)=18/(18+x) (Substitute given values)

4. x=9 (Solve for x)

lmk if there are mistakes in my explanation, hope this helps :)

8 0
3 years ago
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