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k0ka [10]
3 years ago
8

Lucia has 50 sports cards she has 20 football cards 10 baseball card 15 basketball card and five hockey cards a single card is s

elected at a random what is the probability that the card is a football card or basketball card
Mathematics
2 answers:
Ket [755]3 years ago
4 0
The probability that the card is a football card is 20 out of 50 or 40%
the probability that the card is a basketball card is 10 out of 50 or 20%
monitta3 years ago
4 0

Answer: \dfrac{7}{10}

Step-by-step explanation:

Given : Total sports cards = 50

Number of football cards = 20

Number of basketball card = 15

Probability of getting a foot ball card =\dfrac{\text{No. of football card}}{\text{Total carrds}}

=\dfrac{20}{50}

Probability of getting a basketball card =\dfrac{\text{No. of basketball card}}{\text{Total carrds}}

=\dfrac{15}{50}

Since each card is different from another , so the events of drawing any card are independent.

In this case P(foot ball card or basket ball card)= P(foot ball card ) +P(basketball card)

=\dfrac{20}{50}+\dfrac{15}{50}=\dfrac{35}{50}=\dfrac{7}{10}

Thus , the probability that the card is a football card or basketball card is \dfrac{7}{10} .

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1/27 is the awnser i think
5 0
3 years ago
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Bacteria usually reproduce by a process called binary fission. In this type of reproduction, one bacterium divides to
Fed [463]

Answer:

\large \boxed{\text{0.0462 min}^{-1}}

Step-by-step explanation:

One formula for the reproduction of bacteria is

\dfrac{N}{N_{0}} = e^{kt}

Data:

N = 2

N₀ = 1

  t = 15 min

Calculation:

\begin{array}{rcl}\dfrac{N}{N_{0}}& =& e^{kt}\\\\\dfrac{2}{1}& = & e^{k\times15 \text{ min}}\\\\2 & = & e^{15k \text{ min}}\\\ln 2 & = & 15k \text{ min}\\k & = & \dfrac{\ln2 }{\text{15 min}}\\\\& = & \textbf{0.0462 min}^{\mathbf{-1}}\\\\\end{array}\\\text{The value of the constant k is $\large \boxed{\textbf{0.0462 min }^{\mathbf{-1}}}$}

6 0
4 years ago
50 is one tenth of what number?
Stella [2.4K]

Answer:

500

Step-by-step explanation:

Well you find one tenth of a number by dividing it by 10

So to do the opposite, you can do 50*10 which is 500

Or if you really wanted to you could go through each option dividing them all by 10 till you got 50

5 0
3 years ago
Read 2 more answers
Solve for m and n<br> I been stuck on this question for an hour
Crazy boy [7]

Answer:

m = 10 , n = 5\sqrt{2}

Step-by-step explanation:

using the cosine and tangent ratio in the right triangle and the exact values

cos45° = \frac{1}{\sqrt{2} } and tan45° = 1 , then

cos45° = \frac{adjacent}{hypotenuse} = \frac{5\sqrt{2} }{m} = \frac{1}{\sqrt{2} } ( cross- multiply )

m = 5\sqrt{2} × \sqrt{2} = 5 × 2 = 10

-----------------------------------------

tan45° = \frac{opposite}{adjacent} = \frac{n}{5\sqrt{2} } = 1 , then

n = 5\sqrt{2}

3 0
2 years ago
Three numbers are in the ratio 3:9:10. If 10 is added to the last number, then the three numbers form an arithmetic progression.
MrRa [10]

Answer:

<em> The numbers are 6, 18, and 30 </em>

Step-by-step explanation:

If the three numbers are in the ratio of 3:9:10,

let the numbers be 3x, 9x and 10x.

<em>If 10 is added to the last number to form an arithmetic progression</em>

<em>Then, 3x 9x (10x+10) are the progression</em>

The common difference of an arithmetic progression (d) = T₂ - T₁ = T₃ - T₂

T₂-T₁ = T₃ - T₂ .............. Equation 1

Where T₁ = first term of the progression, T₂ = Second term of the progression, T₃ = third term of the progression

<em>Given: T₁ = 3x, T₂ = 9x, T₃ = 10x +10</em>

<em>Substituting these values into equation 1</em>

<em>9x-3x = (10x+10)-9x</em>

<em>Solving the equation above,</em>

<em>3x = 10+x</em>

<em>3x-x = 10</em>

<em>2x = 10</em>

<em>x = 10/2</em>

<em>x = 2.</em>

<em>Therefore the numbers are 6, 18, and 30 </em>

<em />

7 0
3 years ago
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