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3 years ago

Please help me thank you in advance!

Mathematics

1 answer:

Oxana [17]3 years ago

7 0

Answer:

First option: (x+9)^2=81

Step-by-step explanation:

It has the same solution

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What is 6 thousandths of a meter of a decimal

Svetllana [295]

0.006
That's you're answer

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3 years ago

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Find the sum of this infinite geometric series where a1=0.3 and r=0.1

ratelena [41]

Answer:

1/3

Step-by-step explanation:

The formula for computing the sum of an infinite geometric series is

$S=\frac{a_1}{1-r}$ where r is between -1 and 1 and $r$ is the common ratio, and $a_1$ is the first term of the series.

So let's plug in:

$S=\frac{0.3}{1-0.1}$

$S=\frac{0.3}{0.9}$

$S=\frac{3}{9}$ I multiplied bottom and top by 10.

$S=\frac{1}{3}$ I divided top and bottom by 3.

The sum is 1/3.

8 0

3 years ago

The graph of f(x)=cos(x) is transformed to a new function, g(x) , by stretching it horizontally by a factor of 4 and shifting it

SpyIntel [72]

The equation of the new function is $g(x)= cos4 x+1$

Explanation:

The Parent function is $f(x)=cos x$

We need to determine the new function g(x) using the transformation by stretching the f(x) horizontally by a factor of 4 and shifting it 1 unit up.

The function transformation formula is given by

$f(x)=a \cos b(x-c)+d$

Where a stretches the function vertically

b compresses or stretches it horizontally,

c shifts the function left or right

d shifts the function up or down

Since, it is given that the function stretches horizontally by a factor of 4 and shifting it 1 unit up.

Hence, $b=4$ and $d=1$

Substituting these values in the formula, we have,

$g(x)=cos4x+1$

Thus, the equation of the new function is $g(x)= cos4 x+1$

8 0

3 years ago

In preparation for an earnings report, a large retailer wants to estimate p= the proportion of annual sales

mr Goodwill [35]

Using the z-distribution, it is found that the 95% confidence interval for the proportion of sales that occured in December is (0.1648, 0.2948).

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which:

$\pi$ is the sample proportion.

z is the critical value.

n is the sample size.

In this problem, we have a 95% confidence level, hence $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so the critical value is z = 1.96.