it will take 1.33 hours for Braydon and Lauren to get to the same mile marker on the path in the park .
<u>Step-by-step explanation:</u>
Here we have , Braydon can run at 3 miles per hour , he's initially at 10 mile marker . Lauren is at the 12-mile marker at the park, She is walking at a pace of 1.5 miles per hour. We need to find How long will it take for Braydon and Lauren to get to the same mile marker on the path in the park .Let's find out:
Let after time t they meet each other so , Braydon can run at 3 miles per hour , he's initially at 10 mile marker . Distance traveled is given by :
⇒ 
Now , Lauren is at the 12-mile marker at the park, She is walking at a pace of 1.5 miles per hour , Distance traveled is given by :
⇒ 
Equating both we get :
⇒ 
⇒ 
⇒ 
⇒ 
Therefore , it will take 1.33 hours for Braydon and Lauren to get to the same mile marker on the path in the park .
It comes from integrating by parts twice. Let

Recall the IBP formula,

Let


Then

Apply IBP once more, with


Notice that the ∫ v du term contains the original integral, so that




Answer:
I would say that the Answer is 35 I hope this isnt wrong..
Answer:
g(x) is shifted 6 units to the left
Step-by-step explanation:
Lets try to simplify g(x) since has a few extra terms:
g(x)= 3x+12-6=3x+6
Now it is easier to compare the two functions.
We can tell that they both have the same slope, both differs on a extra term
This term tell us that the g(x) is shifted to the left (it is positive 6)
Another approach to the solution is to plot the two functions together by obtaining the crossing points with the 'y' axis and with the 'x' axis
the result is shown in the attached picture
Answer:
210
Step-by-step explanation:
Here comes the problem from Combination.
We are being asked to find the number of ways out in which 3 students may sit on 7 seats in a row. Please see that in this case the even can not be repeated.
Let us start with the student one. For him all the 7 seats are available to sit. Hence number of ways for him to sit = 7
Let us see the student second. For him there are only 6 seats available to sit as one seat has already been occupied. Hence number of ways for him to sit = 6
Let us see the student third. For him there are only 5 seats available to sit as two seat has already been occupied. Hence number of ways for him to sit = 5
Hence the total number of ways for three students to be seated will be
7 x 6 x 5
=210