we know that
For a spherical planet of radius r, the volume V and the surface area SA is equal to

The
ratio of these two quantities may be written as

we know


therefore
the answer is

C^2=a^2+b^2 we are given the hypotenuse of 19 units and one leg of 8 units so:
19^2=8^2+b^2
361=64+b^2
b^2=297
b=√297
b≈17.2 to the nearest tenth
Answer:
see below. The solution is the doubly-shaded area.
Step-by-step explanation:
Each boundary line will be dashed, because the "or equal to" case is <em>not included</em>. Each shaded area will be above the corresponding boundary line because the comparison symbol is y > .... That is, only y-values greater than (above) those in the boundary line are part of the solution.
Of course, the boundary lines are graphed in the usual way. Each crosses the y-axis at the value of the constant in its equation. Each has a slope (rise/run) that is the value of the x-coefficient in the equation.
Gradient =2 because the slope is 2 units. Y-intercept = -2 because it crosses the y-line at -2.