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GarryVolchara [31]
2 years ago
9

HELP ME ON THIS PLSS Kathy swims at least 6 laps everyday. Write an inequality to show how long Kathy swims each day.

Mathematics
1 answer:
mina [271]2 years ago
3 0

Answer:

x ≥ 6.

Step-by-step explanation:

Given : Kathy swims at least 6 laps every day.

To find: Write an inequality to show how long Kathy swims each day.

Solution : We have given that Kathy swims at least 6 laps every day.

We can see from given statement Kathy can swim 6 laps or greater then 6 laps in a day.

Then we use greater than or equal to sign  ( for at least)

Since x ≥ 6.

Therefore, x ≥ 6.

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Vlad [161]

The composite function (g \circle h)(x) works like this:

  • Take a number x as input
  • Evaluate h(x) = 3x. Let's call this output z.
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So, if we substitute back z = 3x, the final output is 1/(3x+2). We know that the denominator of a fraction can't be zero, so we must impose

3x+2 \neq 0 \iff 3x \neq -2 \iff x \neq -\dfrac{2}{3}

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3 years ago
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If David plays 3 tennis matches every week for 9 weeks, how many matches will he play altogether
kari74 [83]
If he plays 3 matches a week for 9 weeks, you have to multiply 3&9.
3*9=27
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Hope this helps:)
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3 years ago
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N - 1/8 = 3/8<br> I am no smort and i forgot to study for a test =|
sdas [7]

Answer:

  • \boxed{\sf{n=\dfrac{1}{2}=0.5 }}

Step-by-step explanation:

Isolate the term of n from one side of the equation.

<h3>n-1/8=3/8</h3>

<u>First, add by 1/8 from both sides.</u>

n-1/8+1/8=3/8+1/8

<u>Solve.</u>

<u>Add the numbers from left to right.</u>

3/8+1/8=4/8

<u>Common factor of 4.</u>

4/4=1

8/4=2

<u>Rewrite as a fraction.</u>

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n=1/2

<u>Divide is another option.</u>

1/2=0.5

n=1/2=0.5

  • <u>Therefore, the final answer is n=1/2=0.5.</u>

I hope this helps you! Let me know if my answer is wrong or not.

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2 years ago
Use the quadratic formula to solve x2 + 9x + 10 = 0.<br> What are the solutions to the equation?
vampirchik [111]

Answer:

\large\boxed{x=\dfrac{-9\pm\sqrt{41}}{2}}

Step-by-step explanation:

\text{The quadratic formula of}

ax^2+bx+c=0

\text{If}\ b^2-4a0,\ \text{then the equation has two solutions}\ x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\=========================================

\text{We have}\ x^2+9x+10=0\\\\a=1,\ b=9,\ c=10\\\\\text{substitute:}\\\\b^2-4ac=9^2-4(1)(10)=81-40=41>0\qquad _{\text{two solutions}}\\\\\sqrt{b^2-4ac}=\sqrt{41}\\\\x=\dfrac{-9\pm\sqrt{41}}{2(1)}=\dfrac{-9\pm\sqrt{41}}{2}

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What is (1.2 x 10^-2) x (3 x 10^5)
liraira [26]

Answer:

B. 3.6 x 10^3

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(1.2 x 10^-2) x (3 x 10^5)

When we multiply terms with powers , we multiply the factors out front and add the exponents

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(1.2 x 10^-2) x (3 x 10^5)   = (1.2* 3) * 10^(-2+5)

                                         = 3.6 * 10 ^3

6 0
3 years ago
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