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a_sh-v [17]
3 years ago
6

I need help on these math questions!

Mathematics
2 answers:
madreJ [45]3 years ago
8 0
The correct answer is a-25x square meters
asambeis [7]3 years ago
4 0
Lets get started :)

The first question requires the area of the circle with a radius of 5 meters

Area formula of a circle is;
A = \pir²
   = \pi(5)² 
   = 25\pi square meters

So your answer will be Option B

The second question asks us to find the area of the remaining rectangle

We have a rectangle with given length to be 10 in and width of 6 in
The Area formula of a rectangle is:
A = length x width
    = 10 x 6
    = 60 in²

We have a triangle within the rectangle with a base of 1.5 in { 10 - 8.5 } and a height of 1.5 in { 6 - 4.5 }
The Area formula of a triangle is:
A = \frac{1}{2} x base x height
    =\frac{1}{2} x 1.5 x 1.5
    = 1.125 in²

For finding the remaining area of the rectangle after removing the triangle, we need to subtract the area of the triangle from the area of the rectangle

Remaining area = Area of rectangle - Area of triangle
                           = 60 - 1.125
                           = 58.875 in²

So your answer will be Option C

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I need help with this . I don’t get how
Svetradugi [14.3K]
Simply collect like terms, numbers and or variables that have the same number and type of variable.

For example 15x^2 and 10x^2 are like terms. Circle the sign in front of the term to perform the correct operation.







5 0
3 years ago
In answering a question on a multiple-choice test, a student either knows the correct answer or guesses it. Let 0.7 be the proba
Dahasolnce [82]

Answer:

The probability is 0.9211

Step-by-step explanation:

Let's call K the event that the student know the answer, G the event that the student guess the answer and C the event that the answer is correct.

So, the probability P(K/C) that a student knows the answer to a question, given that she answered it correctly is:

P(K/C)=P(K∩C)/P(C)

Where P(C) = P(K∩C) + P(G∩C)

Then, the probability P(K∩C) that the student know the answer and it is correct is:

P(K∩C) = 0.7

On the other hand, the probability P(G∩C) that the student guess the answer and it is correct is:

P(G∩C) = 0.3*0.2 = 0.06

Because, 0.3 is the probability that the student guess the answer and 0.2 is the probability that the answer is correct given that the student guess the answer.

Therefore, The probability P(C) that the answer is correct is:

P(C) = 0.7 + 0.06 = 0.76

Finally, P(K/C) is:

P(K/C) = 0.7/0.76 = 0.9211

7 0
3 years ago
BELP ME WITH THIS PLZ!!!!!!
kati45 [8]

Answer:

The entire area of the sailboat is 60cm²

Step-by-step explanation:

You can find the area of this shape by breaking it down into simpler shapes and adding up their individual areas.

In this case, the areas we'll use are the rectangle at the bottom, and the pair of triangles at the top.

Because the two triangles can be put together to form a single triangle, we don't need to measure them independently.  We can simply take the total length of their bases, multiply it by their height, and divide by two.  This follows the rule that the area of a triangle is equal to the area of the square that contains it divided by two.

(2cm + 3cm) × 6cm

= 5cm × 6cm

= 30cm²

The rectangle's area is of course equal to its width times its height, so we can say:

2.5cm × 12cm

= 30cm²

The total area of the shapes then is 30cm² + 30 cm², giving us a total area of 60cm²

3 0
3 years ago
What is 2/3 + 3/4 or 2.3 + 3.4?
rodikova [14]
2/3+3/4=17/12=1.417 This is the anwser
3 0
3 years ago
Read 2 more answers
A manufacturer of chocolate chips would like to know whether its bag filling machine works correctly at the 450 gram setting. It
Arturiano [62]

Answer:

Test statistic = -2.25

P-value = 0.0199

Step-by-step explanation:

We are given the following in the question:  

Population mean, μ = 450 gram

Sample mean, \bar{x} = 441 grams

Sample size, n = 16

Alpha, α = 0.05

Sample variance = 256

\sigma^2 = 256\\\sigma = \sqrt{256} = 16

First, we design the null and the alternate hypothesis

H_{0}: \mu = 450\text{ grams}\\H_A: \mu < 450\text{ grams}

We use one-tailed t test to perform this hypothesis.

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

Putting all the values, we have

t_{stat} = \displaystyle\frac{441 - 450}{\frac{16}{\sqrt{16}} } = -2.25

Now,

Degree of freedom =

=n-1 = 16-1=15

We can calculate the p-value from the table as:

P-value = 0.0199

Conclusion:

Since the p-value is smaller than the significance level we fail to accept the null hypothesis and reject it.

Thus, there is enough evidence to support the claim that the machine is under filling the bags .            

5 0
3 years ago
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