All categories

3 years ago

I need help on these math questions!

Mathematics

2 answers:

madreJ [45]3 years ago

8 0

The correct answer is a-25x square meters

asambeis [7]3 years ago

4 0

Lets get started :)

The first question requires the area of the circle with a radius of 5 meters

Area formula of a circle is;
A = $\pi$ r²
= $\pi$ (5)²
= 25 $\pi$ square meters

So your answer will be Option B

The second question asks us to find the area of the remaining rectangle

We have a rectangle with given length to be 10 in and width of 6 in
The Area formula of a rectangle is:
A = length x width
= 10 x 6
= 60 in²

We have a triangle within the rectangle with a base of 1.5 in { 10 - 8.5 } and a height of 1.5 in { 6 - 4.5 }
The Area formula of a triangle is:
A = $\frac{1}{2}$ x base x height
= $\frac{1}{2}$ x 1.5 x 1.5
= 1.125 in²

For finding the remaining area of the rectangle after removing the triangle, we need to subtract the area of the triangle from the area of the rectangle

Remaining area = Area of rectangle - Area of triangle
= 60 - 1.125
= 58.875 in²

So your answer will be Option C

You might be interested in

In 2 seconds, an elevator travels 40 feet. In 3 seconds, the elevator travels 60 feet. In 4 seconds, the elevator travels 80 fee

professor190 [17]

Y=20x because if it travels 40 in 2 seconds that means in 1 second it traveled 20 so every second the elevator travels 20 so y is the total distance and X is the amount of seconds

5 0

3 years ago

Read 2 more answers

Please help with math and please show your work will give brainliest

Burka [1]

Answer:

The Elimination Method is based on the Addition Property of Equality. The Addition Property of Equality says that when you add the same quantity to both sides of an equation, you still have equality. We will extend the Addition Property of Equality to say that when you add equal quantities to both sides of an equation, the results are equal.

For any expressions a, b, c, and d,

if and then a=bc=da+c=b+d

To solve a system of equations by elimination, we start with both equations in standard form. Then we decide which variable will be easiest to eliminate. How do we decide? We want to have the coefficients of one variable be opposites, so that we can add the equations together and eliminate that variable.

Notice how that works when we add these two equations together:

3x+y=52x−y=0–––––––––––5x=5

The y’s add to zero and we have one equation with one variable.

Let’s try another one:

{x+4y=22x+5y=−2(5.3.3)

This time we don’t see a variable that can be immediately eliminated if we add the equations.

But if we multiply the first equation by −2, we will make the coefficients of x opposites. We must multiply every term on both sides of the equation by −2.

This figure shows two equations. The first is negative 2 times x plus 4y in parentheses equals negative 2 times 2. The second is 2x + 5y = negative 2. This figure shows two equations. The first is negative 2x minus 8y = negative 4. The second is 2x + 5y = -negative 2.

Now we see that the coefficients of the x terms are opposites, so x will be eliminated when we add these two equations.

Add the equations yourself—the result should be −3y = −6. And that looks easy to solve, doesn’t it? Here is what it would look like.

This figure shows two equations being added together. The first is negative 2x – 8y = −4 and 2x plus 5y = negative 2. The answer is negative 3y = negative 6.

We’ll do one more:

{4x−3y=103x+5y=−7

It doesn’t appear that we can get the coefficients of one variable to be opposites by multiplying one of the equations by a constant, unless we use fractions. So instead, we’ll have to multiply both equations by a constant.

We can make the coefficients of x be opposites if we multiply the first equation by 3 and the second by −4, so we get 12x and −12x.

This figure shows two equations. The first is 3 times 4x minus 3y in parentheses equals 3 times 10. The second is negative 4 times 3x plus 5y in parentheses equals negative 4 times negative 7.

This gives us these two new equations:

{12x−9y−12x−20y=30=28

When we add these equations,

\[{12x−9y=30−12x−20y=28–––––––––––––––––−29y=58

the x’s are eliminated and we just have −29y = 58.

Once we get an equation with just one variable, we solve it. Then we substitute that value into one of the original equations to solve for the remaining variable. And, as always, we check our answer to make sure it is a solution to both of the original equations.

Now we’ll see how to use elimination to solve the same system of equations we solved by graphing and by substitution

Step-by-step explanation:

Here is some examples

4 0

2 years ago

Identify the effect on the graph of replacing f(x) by A f(x)

JulijaS [17]

Answer:

See explanation

Step-by-step explanation:

Required

Effect of replacing $f(x)$ with $f(x - h)$

f(x) is represented as: (x,y)

While

f(x - h) is represented as (x - h, y)

Notice the difference in both is that, the x value in f(x - h) is reduced by a constant h while the y value remain unchanged.

This means that the graph of f(x) will shift horizontally (i.e. along the x-axis) to the left by h units

6 0

3 years ago

Write the equation of the line in slope-intercept form that contains the points (4, -1) and (9, 9).

Lesechka [4]

Answer:

y = 2x - 9

Step-by-step explanation:

y2 - y1 / x2 - x1

9 - (-1) / 9 - 4

10 / 5

= 2

y = 2x + b

-1 = 2(4) + b

-1 = 8 + b

-9 = b

5 0

3 years ago

You and a friend go to super taco for lunch. You order three soft tacos and three burritos and your bill totals $11.25. Your fri

Phoenix [80]

Soft tacos are going to be $1.25, and burritos are going to be $2.50

3 0

3 years ago

Read 2 more answers