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3 years ago

8

Select the postulate that is illustrated for the real numbers 6×12=12×6

1 answer:

CaHeK987 [17]3 years ago

8 0

The postulate which is illustrated for the real numbers 6*12 =12*6 is The commutative property of multiplication. This commutative property of multiplication states that whenever we multiply two numbers,we can multiply then in any other. So if we have two numbers a and b,then we can multiply them as a*b or we can multiply them as b*a. We get the same result.

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What is the function rule for the line?

Salsk061 [2.6K]

Answer:

y =2/3x -2

Step-by-step explanation:

The y intercept is -2

The slope is

m = (y2-y1)/ (x2-x1)

Using the points (0,-2) and (3,0)

m = ( 0 - -2)/(3 -0)

= (0+2)/(3-0)

= 2/3

The slope intercept form is

y = mx+b where m is the slope and b is the y intercept

y =2/3x -2

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3 years ago

Find<br>HCF of<br>(726, 255).

Triss [41]

Good evening ,

Answer:

<h2> 3</h2>

Step-by-step explanation:

255 = 3×5×17

726 = 2×3×11^2

Then HCF(255,726) = 3.

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3 years ago

In the same diagram of the staircase railing, what is the value of n? (Picture included)

BaLLatris [955]

Hello,

Angle BCH and CHJ are alternate-interior ( and have the same measure)

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==>n=35

8 0

3 years ago

Read 2 more answers

1. Which of the following is the slope-intercept form of 6x + 2y = 28?

Andru [333]

Answer:

2nd option

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c

Given

6x + 2y = 28 ( subtract 6x from both sides )

2y = - 6x + 28 ( divide the terms by 2 )

y = - 3x + 14 ← in slope- intercept form

6 0

2 years ago

Read 2 more answers

2x^3-x^2+x-2 factorize

bekas [8.4K]

Answer:

$(x-1)(2x^2+x+2)$

Step-by-step explanation:

Factorize:

$f(x)=2x^3-x^2+x-2$

<u>Factor Theorem</u>

If f(a) = 0 for a polynomial then (x - a) is a factor of the polynomial f(x).

Substitute x = 1 into the function:

$\implies f(1)=2(1)^3-1^2+1-2=0$

Therefore, (x - 1) is a factor.

As the polynomial is cubic:

$\implies f(x)=(x-1)(ax^2+bx+c)$

Expanding the brackets:

$\implies f(x)=ax^3+bx^2+cx-ax^2-bx-c$

$\implies f(x)=ax^3+(b-a)x^2+(c-b)x-c$

Comparing coefficients with the original polynomial:

$\implies ax^3=2x^3 \implies a=2$

$\implies (b-a)x^2=-x^2 \implies b-2=-1 \implies b=1$

$\implies -c=-2 \implies c=2$

Therefore:

$\implies f(x)=(x-1)(2x^2+x+2)$

Cannot be factored any further.

4 0

2 years ago

Read 2 more answers