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3 years ago

Compare the size of 1 meter to the size of 1 centimeter. use your meterstick to help.

1 answer:

4 0

This seems like a simple conversion problem. 1m=?cm and 1cm=?m.

Since this uses the metric system, you know the general layout of the prefixes: K H D M d c m. I remember this as King Henry died Monday drinking chocolate milk, but as long as you remember it you're good.

Let's look at 1m. Centimeters is two places away from it
K H D (M) d (c) m
This means you move the decimal place to the right two times, so 1 meter is equal to 100 centimeters.

For 1 cm, the meter position is two places away. This means we have to move the decimal place to the left two times. So, 1 centimeter is equal to 0.01 meters.

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You buy a ring box as a birthday gift that is in the shape of a triangular prism. What is the least amount of wrapping paper nee

SashulF [63]

<span>If the condition means conventional/regular rectangular piece of paper, then it is, probably,
rectangle of 8+3+3 = 14 inches wide and 3+10+3+10 = 26 inches long.</span>

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3 years ago

write and solve the differential equation that models the following statment. "the rate if change of W with respect to x is prop

Vaselesa [24]

Answer:

$\int k(x + 18)dx = \int kx + 18k dx$ = $k\frac{x^{2} }{2}$ + $18kx$ + C where C is the constant of integration.

Step-by-step explanation:

i)it is given that the rate of change of W with respect to x is proportional to

x + 18. Therefore $\frac{dW}{dx}$ = k(x + 18) where k is a constant.

ii) Therefore $\int k(x + 18)dx = \int kx + 18k dx$ = $k\frac{x^{2} }{2}$ + $18kx$ + C where C is the constant of integration.

iii) the complete solution can only be found if we know the constant of proportion and also the constant of integration.

4 0

3 years ago

Solve each system of equations by graphing.

fredd [130]

Answer:

1. X=-3, Y=0

2. all real numbers

Step-by-step explanation:

2x+x+3=-6

3x+3=-6

3x=-9

x=-3

y=-3+3

y=0

6x-2(3x-6)=12

6x-6x+12=12

0=0

All real numbers

3 0

3 years ago

What is -8(v-3) = -2(-3v-5)

Scilla [17]

The answer is 1. v=1 because it eventually ends up being 7v=7 and it divides into 1.

6 0

3 years ago

You throw a ball at a height of 6 feet above the

Alexandra [31]

Answer:

0.375 second and 3.5 second

Step-by-step explanation:

The position can be modeled by a quadratic function $\displaystyle{h=-16t^2+62t+6}$ . We are tasked to find the time when a ball reaches a height of 27 feet. Therefore, let h = 27:

$\displaystyle{27=-16t^2+62t+6}$

Solve for t:

$\displaystyle{27-6=-16t^2+62t}\\\\\displaystyle{21=-16t^2+62t}\\\\\displaystyle{16t^2-62t+21=0}$

Since the equation is quite complicated and more time-consuming to solve, i'll skip the factoring or quadratic part:

$\displaystyle{t=0.375, 3.5}$

After done solving the equation, you'll get t = 0.375 and 3.5 seconds. These solutions are valid since both are positive values and time can only be positive.

Hence, it'll take 0.375 and 3.5 seconds for a ball to reach 27 feet.

3 0

2 years ago