<span>The 3rd astronaut would catch the 2nd astronaut and throw the 2nd astronaut towards the 1st and the game would end there.
The key thing to remember is conservation of momentum. Since all of the astronauts have the same mass and strength, I will be introducing a unit called "A" which represents the maximum momentum that one astronaut can produce while throwing another. So here's the game of catch, throw by throw.
Before the game begins, I will assume all three astronauts are stationary and have 0 momentum. So
Astronaut 1 = 0 A (Stationary, next to astronaut 2)
Astronaut 2 = 0 A (Stationary, next to astronaut 1)
Astronaut 3 = 0 A (Stationary)
1st astronaut grabs the 2nd astronaut and throws him towards the 3rd.
Since every action has an equal and opposite reaction, what will happen is the 1st astronaut will be sent moving backwards with a momentum of -1/2A and the 2nd astronaut will be heading towards the 3rd with a momentum of +1/A. So we're left with
Astronaut 1 = -1/2 A (Moving to the left)
Astronaut 2 = +1/2 A (Moving to the right)
Astronaut 3 = 0 A (Stationary)
Now the 3rd astronaut catches the 2nd who was thrown at him. Both of them continue moving in the same direction as the 2nd astronaut was just prior to being caught, but at a reduced velocity, giving
Astronaut 1 = -1/2 A (Moving to the left)
Astronaut 2 = +1/4 A (Moving to the right, slowly)
Astronaut 3 = +1/4 A (Moving to the right, slowly)
Finally, Astronaut 3 throws astronaut 2 back towards Astronaut 1, giving
Astronaut 1 = -1/2 A (Moving to the left)
Astronaut 2 = +1/4 A -1/2A = -1/4A (Moving to the left, slowly)
Astronaut 3 = +1/4 A +1/2A = +3/4A (Moving to the right, rapidly)
So what you're left with is Astronaut 1 moving to the left faster than Astronaut 2, so those two astronauts will never catch each other. Meanwhile, Astronaut 3 is moving to the right and getting further and further away from the other 2 astronauts. So none of the astronauts will ever be able to catch or throw anyone ever again.</span>
Answer:
Step-by-step explanation:
I know that there is a zero and a 1 involved in this somewhere. The only answer I can get which is a bit of a cheat, is
1^0! = 0!^1
These are not exactly the same thing. The trouble is that they are equal. There is a difference between "not the same thing" and "equal."
If I think of something else, I'll put it in a comment.
Answer:
21.6 liters
Step-by-step explanation:
40 drops make up a volume of 10 mL
Therefore, the volume of 1 drop of water = 10mL/40 = 1/4 mL= 0.25mL
Since the tap loses 1 drop of water in 1 sec, it loses 0.25mL of water in 1 second
60 seconds make up 1 second so volume of water lost in 1 minute = 0.25 x 60 = 15 mL
60 minutes make up 1 hour so volume of water lost in 1 hour = 15 x 60 = 900 mL
24 hours make up a day so volume of water lost in 1 day = 900 x 24 = 21,600 mL
Since 1000 mL make up 1 liter, divide by 1000 to get volume in liters
Volume of water lost in 1 day = 21600/1000 = 21.6 liters
Can be done as one equation
V lost in one day = 0.25 x 3600 x 24 mL = 21600 mL = 21.6 L
Answer:
Step-by-step explanation:
Answer:
i wish i knew
Step-by-step explanation:
i wanted to type
