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hjlf
3 years ago
11

The owner of a baseball stadium found that he sells an average of 586 tickets to each game when he charges an average of $59 per

ticket. In addition, he found that with every $6 increase in ticket price, the average number of tickets sold decreases by an average of 4.
Which of the following functions describes the baseball stadium's profit in terms of x, the number of $6 increases over $59?

A.
P(x) = $34,574 + $3,280x - $24x2

B.
P(x) = $34,574 + $3,516x

C.
P(x) = $59 + $3,280x

D.
P(x) = $59 - $3,752x - $24x2
Mathematics
1 answer:
NeX [460]3 years ago
7 0

Answer:

A: 34574+3280x-24x^2

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Answer:

the third one ( -7+u+8t)

Step-by-step explanation:

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You invest $12,000 at 3.8% annual interest compounded annually. How much will you have at the end of 5 years?
Serjik [45]

Answer:

The answer is 60,000.

Step-by-step explanation:

If you invest 12,000 at 3.8 annual interest.  Annual means yearly, so that's every year. 12,000 x 5 is 60,000 that's why the answer is 60,000. If the answer is incorrect or correct let me know. If it's correct, mark me as brainlest, give me a rating, or say thank you! Have A Great Day.

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3 years ago
Plant A: A graph has time (weeks) on the x-axis, and height (inches) on the y-axis. A line goes through points (0, 3), (1, 4.8),
butalik [34]

Answer:

The correct option is;

No, The greater rate of change of Plant A will result in it being 0.9 inches taller in 6 weeks

Step-by-step explanation:

The parameters given are;

Plant A:

Weeks,    Height

0,               3

1,                4.8

2,               6.6

3,               8.4

The rate of change of height, H per week, t,\left (\dfrac{dH}{dt} \right )  for plant A per week is therefore;

\dfrac{dH}{dt} =  \dfrac{H_n - H_{(n-1)} }{t_n - t_{(n-1)}} = \dfrac{8.4 - 3 }{3 - 0} = \dfrac{5.4}{3} = 1.8 \ inches/week

Therefore we have;

H = 1.8 × t + 3

At week 6,

H = 3 + 6×1.8 = 13.8 inches

Plant B

Weeks,    Height

2,               7.3

3,               8.7

4,               10.1

The rate of change of height, H per week, t,\left (\dfrac{dH}{dt} \right )  for plant B per week is given as follows;

\dfrac{dH}{dt} =  \dfrac{H_n - H_{(n-1)} }{t_n - t_{(n-1)}} = \dfrac{10.1 - 7.3 }{4 - 2} = \dfrac{2.8}{2} = 1.4 \ inches/week

Therefore we have;

When t = 2, H = 7.3 hence, 7.3 = 2 × 1.4 + H₀

Where:

H₀ = H at t = 0

H₀ = 7.3 - 2 × 1.4 = 4.5

At week 6 we have;

H = 4.5 + 6×1.4 = 12.9 inches

Which indicates that Plant A will be 0.9 inches taller than Plant B at week 6.

The correct option is therefore;

No, The greater rate of change of Plant A will result in it being 0.9 inches taller in 6 weeks.

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Answer:

the answer is B {(0,-4),(2,6)(,4,16)

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3 years ago
Write .139 as a percent.
Rama09 [41]

Answer:

13.9%

Step-by-step explanation:

0.139 x 100=13.9, can you give me brainiest if its correct

4 0
3 years ago
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