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creativ13 [48]
2 years ago
8

Solve the equation. -2(4 + 3x) = 3(x - 2)

Mathematics
2 answers:
ale4655 [162]2 years ago
8 0

Answer:

<h2><u><em>x = - 2/9</em></u></h2>

Step-by-step explanation:

Solve the equation.

-2(4 + 3x) = 3(x - 2)

-8 - 6x = 3x - 6

-8 + 6 = 3x + 6x

-2 = 9x

x = - 2/9

anygoal [31]2 years ago
3 0

Answer:

-2\9

OR

-0.2

Step-by-step explanation:

−2(4+3x)=3(x−2)

Use the distributive property to multiply −2 by 4+3x.

-

−8−6x=3(x−2)

Use the distributive property to multiply 3 by x−2.

-

−8−6x=3x−6

Subtract 3x from both sides.

−8−6x−3x=−6

-

Combine −6x and −3x to get −9x.

−8−9x=−6

Add 8 to both sides.

−9x=−6+8

-

Add −6 and 8 to get 2.

−9x=2

Divide both sides by −9.

x = 2\-9

Fraction 2\-9  can be rewritten as -2\9 by extracting the negative sign.

SO..

ANSWER IS = -2\9

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b. There is no evidence that the population mean is above $300.

c. There is no evidence that the population mean is above $300.

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Step-by-step explanation:

Let X be the random variable that represents the cost of textbooks. We have observed n = 25 values, \bar{x} = 315.4 and s = 43.20. We suppose that X is normally distributed.

We have the following null and alternative hypothesis

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We will use the test statistic

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If H_{0} is true, then T has a t distribution with n-1 = 24 degrees of freedom.

a. The rejection region is given by RR = {t | t > t_{0.9}} where t_{0.9} = 1.3178 is the 90th quantile of the t distribution with 24 df, so, RR = {t | t > 1.3178}. Because the observed value satisty 1.7824 > 1.3178, there is evidence that the population mean is above $300.

b. If s = 75, then the observed value is t_{0} = \frac{315.4 - 300}{75/\sqrt{25}} = 1.0267. The rejection region for a 0.05 level of significance is RR = {t | t > t_{0.95}} where t_{0.95} = 1.7108 is the 95th quantile of the t distribution with 24 df, so, RR = {t | t > 1.7108}. Because the observed value does not fall inside the rejection region, there is no evidence that the population mean is above $300.

c. If \bar{x} = 305.11 and s = 43.20, the observed value is t_{0} = \frac{305.11 - 300}{43.20/\sqrt{25}} =  0.5914. For RR = {t | t > 1.3178} we have that the observed value does not fall inside RR, therefore, there is no evidence that the population mean is above $300.

d. Because the director of admissions is concerned about the high cost of textbooks, and there is evidence that the population mean of costs is above $300, the director could ask for cheaper similar books.

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Answer:

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Step-by-step explanation:

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