Answer:
YES MA'AM
Step-by-step explanation:
Here we're applying a basic physics rule for vertical motion where the only pull on the object is gravity.
This rule has the form
h(t) = h + v t + (1/2)a*t^2
o o
To adapt this rule to this particular question replace h with 0, as the
o
upward path of the object begins at 0 ft. Replace v with +15 ft/sec.
o
Replace "a" with (-32.2 ft/(sec^2); this is the acceleration due to gravity.
Then we have the following, with the label F(t):
F(t) = 0 + (15 ft/sec)t + (1/2)(-32.2 ft)/(sec^2), or
F(t) = 15t - 16.1t^2. Thus, Choice D is correct.
Please note: To avoid confusion, please use " ^ " to denote exponentiation:
F(t) = -16t^2 + 15t
Since we know x=6, replace all the x with 6 in the equation and then follow the PEMDAS rule. y= -2(6)^2 + 2(6) + 2 y= -2 (36) + 2 (6) + 2 y= -72 + 12 + 2 y= -60+2 y= -58
Answer:
32.75
Step-by-step explanation:
N I believe but I’m not too sure
