Answer:
The average angle at which the airplane must descend for landing is 21°
Step-by-step explanation:
Here, we have question related to angle of elevation and depression
The height of the airplane be, y = 10,000 ft
The Location of the airport is, x = 50 miles = 26400 ft
Therefore,
we have,
Let the average angle be θ
Therefore,
The opposite to the angle of descent is the height and the adjacent is the distance of the airport away from the airplane
Therefore, tan θ = 
Therefore, the average angle θ = tan⁻¹ 0.379 = 20.746 ° ≈ 21°.
Answer:
(4,-3) Domain: 4. (8,8) Domain: 8. (0,-3) Domain: 0. (8,1) Domain: 8 (4,3) Domain: 4
Answer:
Notice the line in between the 61 degrees and b
Step-by-step explanation:
I can't remember what this kind of angle is called, but when you have a straight line with another line coming out of it like this, then the sum of both angles has to equal 180 so what would you add to 61 to get to 180?
When we bring 6y from right side to left side it’s sign get changed and 8y-6y=2y.
Answer:
Rather than just multiplying 5/4 with 8, she has to multiply it with 3 + 8. She could put parentheses around the 3 + 8, according to PEMDAS, this would mean that the parenthesis must be solved before multiplication. The correct answer would be:
4/5x - 8 = 3
4/5x = 3 + 8
x = (3 + 8)5/4
x = 11 x 5/4
x = 55/4 or 13.75
