4х = 32 А. x= 9 В. x= 8 с. x= 28 D. х = 128
1 answer:
You might be interested in
I'm assuming all of (x^2+9) is in the denominator. If that assumption is correct, then,
One possible answer is
Another possible answer is
There are many ways to do this. The idea is that when we have f( g(x) ), we basically replace every x in f(x) with g(x)
So in the first example above, we would have
In that third step, g(x) was replaced with x^2+9 since g(x) = x^2+9.
Similar steps will happen with the second example as well (when g(x) = x^2)