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Lisa [10]
3 years ago
13

99 POINTS

Mathematics
1 answer:
inysia [295]3 years ago
5 0

Answer:

Part a) The exact area of the sidewalk is 80\pi\ m^{2}

Part b) The approximate area of the sidewalk is 251.2\ m^{2}

Step-by-step explanation:

we know that

The area of the sidewalk is equal to the area of the outer circle minus the area of the inner circle

Part a) Find the exact area of the sidewalk

A=\pi (12)^{2} -\pi (8)^{2}

A=\pi [144-64]

A=80\pi\ m^{2}

Part b) Find the approximate area of the sidewalk

assume \pi=3.14

substitute

A=80(3.14)=251.2\ m^{2}

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Step-by-step explanation:

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3 years ago
How do you do this? It’s factoring polynomials by the way.
galben [10]
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8 0
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Let S be a sample space and E and F be events associated with S. Suppose that
Oksanka [162]

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a) P(E|F) = 0.5

b) P(F|E) = 0.167

c) P(E|F') = 0.625

d) P(E′|F′) = 0.375

Step-by-step explanation:

P(E) = 0.6

P(F) = 0.2

P(E n F) = 0.1

a) P(E|F) = Probability of E occurring, given F has already occurred. It is given mathematically as

P(E|F) = [P(E n F)]/P(F) = 0.1/0.2 = 0.5

b) P(F|E) = Probability of F occurring, given E has already occurred. It is given mathematically as

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c) P(E|F′) = Probability of E occurring, given F did not occur. It is given mathematically as

P(E|F') = [P(E n F')]/P(F')

But P(F') = 1 - P(F) = 1 - 0.2 = 0.8

P(E n F') = P(E) - P(E n F) = 0.6 - 0.1 = 0.5

P(E|F') = 0.5/0.8 = 0.625

d) P(E′|F′) = [P(E' n F')]/P(F')

P(F') = 0.8, P(Universal set) = P(U) = 1

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P(E′|F′) = 0.3/0.8 = 0.375

7 0
3 years ago
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