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vova2212 [387]
3 years ago
15

Item 1

Mathematics
1 answer:
Musya8 [376]3 years ago
3 0

Answer:

C = 1.50t + 5

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Step-by-step explanation:

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Research suggests that about 60% of CSU graduates started at a community college. In random samples of 100 CSU graduates, the pe
Nesterboy [21]

Answer:

The probability that in a random sample of 100 CSU graduates the error is within 5% of the population proportion of 60% is 0.6923.

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes <em>n</em> > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

 \mu_{\hat p}=p

The standard deviation of this sampling distribution of sample proportion is:

 \sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}

The information provided is:

<em>p</em> = 0.60

<em>n</em> = 100

As <em>n</em> = 100 > 30, the central limit theorem can be applied to approximate the sampling distribution of sample proportions.

The distribution of sample proportion is \hat p\sim N(0.60, 0.049^{2}).

Compute the probability that in a random sample of 100 CSU graduates the error is within 5% of the population proportion of 60% as follows:

P(|\hat p-\mu_{\hat p}|=0.05)=P(-0.05

                             =P(\frac{-0.05}{0.049}

Thus, the probability that in a random sample of 100 CSU graduates the error is within 5% of the population proportion of 60% is 0.6923.

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