What are two equivalent ratios for 8:4
2 answers:
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Answer:
16Km due east of school P
Step-by-step explanation:
Given
A school P is 16km due west of a school Q
Thus, we can say that distance PQ = 16 km.
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now we have to find the bearing of Q from P
As distance is same
distance PQ = distance QP
Thus,
Distance will remain same of 16 km.
For direction,
If Q is west of P, then P will be east of Q
as shown in figure P is west of Q,
now from point P , Q is west P.
Thus,
Bearing of School Q from P is 16Km due east of school P
Place the decimal point right after the first nonzero digit, which is 3.
So you'll go from this
to this 
after this move.
Now ask yourself: "how many spots must I move the decimal point to get back to 0.003045?"
The answer is "3 spots to the left"
The exponent of the final answer is -3
The negative indicates "move left" and the 3 tells us how many places to move the decimal
Therefore,
Answer: Choice C)
This is assuming you meant to write the -3 as an exponent
So you'll go from this
Now ask yourself: "how many spots must I move the decimal point to get back to 0.003045?"
The answer is "3 spots to the left"
The exponent of the final answer is -3
The negative indicates "move left" and the 3 tells us how many places to move the decimal
Therefore,
Answer: Choice C)
This is assuming you meant to write the -3 as an exponent