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storchak [24]
3 years ago
15

The vocabulary not understand this

Mathematics
1 answer:
Alja [10]3 years ago
8 0
1. square root

2. irrational number

3. positive
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Given the following list of numbers, find the mean. 5,6,12,2,5,12,14
mezya [45]

Answer:

the mean is 8

Step-by-step explanation:

added them all together and divided by 7

8 0
2 years ago
7. Melissa bought 8 yards of string to make bracelets. She wants to cut the string in equal pieces that is 1/2 yard
ratelena [41]

Answer:

16 i think

Step by Step Explanation:

4 0
3 years ago
Read 2 more answers
How do you verify factoring is correct?
Ivahew [28]
Multiply the factors together. You should get the original expression.

For example, if we are to factor
2x^2 + 4x
we would factor as
2x(x + 2).
Check this by multiplying back in
2x*x + 2x*2 = 2x^2 + 4x
which is what we started with, so we know we are correct.
5 0
3 years ago
What is the function written in vertex form?
lys-0071 [83]

Answer:

The answer in the procedure

Step-by-step explanation:

The question does not present the graph, however it can be answered to help the student solve similar problems.

we know that

The equation of a vertical parabola into vertex form is equal to

f(x)=a(x-h)^{2}+k

where

a is a coefficient

(h,k) is the vertex

If the coefficient a is positive then the parabola open up and the vertex is a minimum

If the coefficient a is negative then the parabola open down and the vertex is a maximum

case A) we have

f(x)=3(x+4)^{2}-6

The vertex is the point (-4,-6)

a=3

therefore

The parabola open up, the vertex is a minimum

case B) we have

f(x)=3(x+4)^{2}-38

The vertex is the point (-4,-38)

a=3

therefore

The parabola open up, the vertex is a minimum

case C) we have

f(x)=3(x-4)^{2}-6

The vertex is the point (4,-6)

a=3

therefore

The parabola open up, the vertex is a minimum

case D) we have

f(x)=3(x-4)^{2}-38

The vertex is the point (4,-38)

a=3

therefore

The parabola open up, the vertex is a minimum

4 0
3 years ago
Given triangle ABC with coordinates A(−6, 4), B(−6, 1), and C(−8, 0), and its image A′B′C′ with A′(−2, 0), B′(−5, 0), and C′(−6,
Zinaida [17]

Answer:

  The line of reflection is at y = x+6.

Step-by-step explanation:

The perpendicular bisector of AA' is a line with slope 1 through the midpoint of AA', which is (-4, 2). In point-slope form, the equation is ...

  y = 1(x +4) +2

  y = x + 6 . . . . . . . line of reflection

6 0
3 years ago
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