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3 years ago

Which equation is represented by the intersection of the graphs below? Image is above.

Mathematics

1 answer:

zaharov [31]3 years ago

3 0

Option B:

sin x = 1 is the equation represented by the intersection of the graph.

Solution:

The graph lies between -1 and 1 in y-axis.

x-axis of the graph is all real numbers.

The graph oscillates between -1 and 1 and a shape that repeats itself every 2π units.

That is the domain of the graph is all real numbers.

The range of the graph is [-1, 1].

It clearly shows that, it is the graph of sinx = 1.

Hence sin x = 1 is the equation represented by the intersection of the graph.

Option B is the correct answer.

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Julie bought some shirts for six each the mark Marge bought some shirts for eight dollars each the girls spend the same amount o

Juliette [100K]

Answer:

24 dollars

Step-by-step explanation:

6 12 18 24

8 16 24

the first to match up is 24 so that is the least they could have spent

8 0

3 years ago

Please help I’m a bit confused on this I appreciate answers!

Afina-wow [57]

Answer:

$(2x^3)^3=8\cdot x^{9}$

Step-by-step explanation:

<u>Properties of Exponents</u>

The property called Power to a Power shows us how to simplify expressions of the type:

$(x^n)^m=x^{n*m}$

Similarily the property called Power of a product simplifies expressions like:

$(x.y)^n=x^n.y^n$

The company mentioned in the question uses the expression

$(2x^3)^3$

millimeters per second to calculate the maximum capacity of a photocell with an area of x^3 square millimeters.

First, use the power of a product property:

$(2x^3)^3=2^3\cdot (x^3)^3$

Now use the power to a power property:

$(2x^3)^3=2^3\cdot x^{3*3}$

Operate:

$\mathbf{(2x^3)^3=8\cdot x^{9}}$

5 0

3 years ago

What is the range of the set of data : 13, 16, 10, 15, 6, 6

aniked [119]

The range is the difference between the largest and smallest number. So for those numbers the lowest value is 6 and the highest is 16. So 16 - 6 = 10

So the range is 10

6 0

3 years ago

Find the value of the integral that converges.<br> ∫^-5_-[infinity] x^-2 dx.

Bingel [31]

Answer:

$\int_{-\infty}^{-5} x^{-2}dx= \frac{1}{5} + \lim_{x\to -\infty} \frac{1}{x} =\frac{1}{5}$

Because the $\lim_{x\to -\infty} \frac{1}{x} =0$

The integral converges to $\frac{1}{5}$

Step-by-step explanation:

For this case we want to find the following integral:

$\int_{-\infty}^{-5} x^{-2}dx$

And we can solve the integral on this way:

$\int_{-\infty}^{-5} x^{-2}dx= \frac{x^{-2+1}}{-2+1} \Big|_{-\infty}^{-5}$

$\int_{-\infty}^{-5} x^{-2}dx= -\frac{1}{x} \Big|_{-\infty}^{-5}$

And if we evaluate the integral using the fundamental theorem of calculus we got:

$\int_{-\infty}^{-5} x^{-2}dx= \frac{1}{5} + \lim_{x\to -\infty} \frac{1}{x} =\frac{1}{5}$

Because the $\lim_{x\to -\infty} \frac{1}{x} =0$

The integral converges to $\frac{1}{5}$

8 0

3 years ago

Use what you know about decimals or fractions to explain why (0.2)•(0.002)=0.0004

strojnjashka [21]

Answer:

So any time you are multiplying something, you are making "groups of"

so 3 groups of 2 = 6, 4 groups of 3 = 12

But with decimals or fractions, because they are a value less than zero, the numbers become increasingly small instead of bigger, like standard multiplication.

So for example, 1 group of 1/2 = 1/2

2 groups of 1/4 = 1/2

and so on

hope this helps!

6 0

3 years ago