Answer:
Distance of JK = 15 unit
Step-by-step explanation:
Given:
J(4,8)
K(-1,-2)
Find:
Distance of JK
Computation:
Distance = √(x₂-x₁)² + (y₂-y₁)²
Distance of JK = √(-1-4)² + (-2-8)²
Distance of JK = √25 + 100
Distance of JK = √125
Distance of JK = 15 unit
Sound or vibration wave that is conducted
Let's solve and find out.
4(2n - 4) + 3 = 8n - 19
8n - 16 + 3 = 8n - 19
8n - 13 = 8n - 19
-13 = -19
-13 and -19 are not equal, so the equation has no solutions.
Answer:
A. 0
<span>E[Y] = 0.4·1 + 0.3·2 + 0.2·3 + 0.1·4 = 2
E[1/Y] =0.4·1/1 + 0.3·1/2 + 0.2·1/3 + 0.1·1/4 = 0.4 + 0.15 + 0.0666 + 0.025?0.64
V[Y] =E[Y2]-E[Y]2= (0.4)·12+(0.3)·22+(0.2)·32+(0.1)·42-22= 0.4+1.2+1.8+1.6-4= 5-4 = 1</span>
Answer:
z = 4/5
Step-by-step explanation:
3(5z + 7) = 33
Divide each side by 3
3/3(5z + 7) = 33/3
5z+7 = 11
Subtract 7 from each side
5z+7-7 = 11-7
5z = 4
Divide by 5
5z/5 = 4/5
z = 4/5
