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fredd [130]
3 years ago
12

If the factors of function f are (x-6) and (x - 1), what are the zeros of function f?

Mathematics
1 answer:
Masteriza [31]3 years ago
8 0
Set each factor to zero
X-6=0
X-1=0
Solve for X
X=6
X=1
Therefore, the answer is C
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Solve each system by elimination by multiplying both equations. eliminate y first. show all work.
Alex17521 [72]
First \mathrm{Multiply\:}10x-3y=18\mathrm{\:by\:}3:\quad 30x-9y=54
Then \mathrm{Multiply\:}6x-10y=-22\mathrm{\:by\:}5:\quad 30x-50y=-110
To get \begin{bmatrix}30x-9y=54\\ 30x-50y=-110\end{bmatrix}
So...
30x-50y=-110 \ \textgreater \  \begin{bmatrix}30x-9y=54\\ -41y=-164\end{bmatrix}
-41y=-164 \ \textgreater \  \mathrm{Divide\:both\:sides\:by\:}-41 \ \textgreater \  \frac{-41y}{-41}=\frac{-164}{-41}
To get y = 4.
\mathrm{For\:}30x-9y=54\mathrm{\:plug\:in\:} \:y=4 \ \textgreater \  30x-9\cdot \:4=54
\mathrm{Multiply\:the\:numbers:}\:9\cdot \:4=36 \ \textgreater \  30x-36=54 \ \textgreater \
Next \mathrm{Add\:}36\mathrm{\:to\:both\:sides} \ \textgreater \  30x-36+36=54+36 \ \textgreater \  \mathrm{Simplify} \ \textgreater \  30x=90
Finally \mathrm{Divide\:both\:sides\:by\:}30 \ \textgreater \  \frac{30x}{30}=\frac{90}{30} \ \textgreater \  x = 3
Therefore our solutions are y = 4, x = 3
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3 years ago
-4x + 40 &gt; -4<br> Solve quick le,ase
emmasim [6.3K]

Answer:

x>-39

Step-by-step explanation:

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Step-by-step explana1tion:

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soldi70 [24.7K]

Answer:

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Step-by-step explanation:

The circumference of the ball is found from ...

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